All categories

3 years ago

The absolute value function is one-to-one, while the greatest integer function is many-to-one.

Mathematics

2 answers:

Molodets [167]3 years ago

7 0

Answer:

Option B that is false.

Step-by-step explanation:

The above statement is false because

Absolute value function is not one-one

For example:

|x|=x and |-x|=x

We are getting one vale at two different points.

And greatest integer function is many to one that is correct because

it will consider only the integer part

for example:

[1.05]=1 ,[1.02]=1 ,[1.06]=1 ,[1.08]=1

Hence, many to one

Nut one if false one is true

Hence, entirely it would be a false statement

s344n2d4d5 [400]3 years ago

5 0

The absolute value function is one-to-one, while the greatest integer function is many-to-one.

Answer: The statement shown above is false. The absolute value function is not not one to one, and the greatest integer function is not many to one. Therefore the correct answer choice is B) False. The best way to find whether a function is one to one is explained in the attachment.

I hope it helps, Regards.

You might be interested in

An Expression that represents 40% of a number is 40n

kumpel [21]

Is this a true or false question?

5 0

3 years ago

Read 2 more answers

What goes where. JdhshshHshxjancixd

valentina_108 [34]

Answer:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

Step-by-step explanation:

We need to simplify

$y + \frac{2}{5}y$

We collect LCM to get;

$\frac{5y + 2y}{5} = \frac{7y}{5}$

Therefore:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

Also we need to simplify:

$y - \frac{2}{5}y$

We collect LCM to get;

$y - \frac{2}{5}y = \frac{5y - 2y}{5} = \frac{3}{5} y$

Therefore

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

5 0

3 years ago

three vertices of a rectangle are located at (5,3), (7,1), and (1,-1). what are the coordinates of the fourth vertex?

SVETLANKA909090 [29]

I first plotted the three points and from from their position it was clear which pairs to join to start a rectangle.

At this point you need to check to make sure the angle at B is a right angle. Find the slope of the line segments AB and BC and check that the product of the slopes is -1.

From the diagram you can now see where the fourth point D has to be. If AB and CD are parallel then D must be 3 units to the left of C and 2 units above C. Find the coordinates of D and then check by finding the slopes of CD and DA and showing that the angle at D is a right angle.

I hope this helps