? Use a graphing app if you can
Answer:
the ingegral I=π/4
Step-by-step explanation:
From the integral
I=∫0-1∫0-sqrt(1-y^2) (x^2 + y^2) dxdy
from polar coordinates
r²=x² + y²
then for r=1
√(1- y²) = x
for y=1 → x=0 , for y=0 → x=1
then the integration area is a hemisphere or radius r=1
therefore
I= ∫0-1∫0-sqrt(1-y^2) (x^2 + y^2) dxdy = (1/2)∫2π-0 ∫1-0 r² *r drdθ ( the additional r is due to the Jacobian of the transformation to polar coordinates , 1/2 because is an hemisphere so it would be the half of the value of the total sphere)
I= (1/2)∫2π-0 ∫1-0 r³drdθ = (1/2)∫2π-0 (1⁴/4 - 0⁴/4) dθ = (1/2)∫2π-0 (1/4)*dθ = (1/2)*(1/4)*2π = π/4
Answer:
r = 3x + 1
Step-by-step explanation:
The area (A) of a circle is calculated as
A = πr² ( r is the radius )
Here
πr² = π(9x² + 6x + 1) ← divide both sides by π
r² = 9x² + 6x + 1 ← perfect square
r² = (3x + 1)² , thus
r = 3x + 1
Answer:b
Step-by-step explanation:
