The answer is b. Hope this was helpful
The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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Y = mx + b
slope(m) = 3/4
(5,-4)...x = 5 and y = -4
now we sub
-4 = 3/4(5) + b
-4 = 15/4 + b
-4 - 15/4 = b
-16/4 - 15/4 = b
- 31/4 = b....or - 7 3/4 = b
so ur equation is : y = 3/4x + (-31/4) or y = 3/4x - 31/4
