Formula is y = a(x-h)^2 + k
Where h is 1 and k is 1
f (x) = a(x-1)^2 + 1
-3 = a(0-1)^2 + 1
-3 = a(-1)^2 + 1
-3 = a(1) + 1
-3 - 1 = a
-4 = a
a = -4
A must be equal to -4
y = -4(x-1)^2 + 1
0 = -4(x-1)^2 + 1
4(x^2 - 2x + 1) - 1 = 0
4x^2 - 8x + 4 - 1 = 0
4x^2 - 8x + 3 = 0
4x^2 - 8x = -3
Divide fpr 4 each term of the equation....x^2 - 2x = -3/4
We must factor the perfect square ax^2 + bx + c which we don't have. We must follow the rule (b/2)^2 where b is -2....(-2/2)^2 =
(-1)^2 = 1 and we add up that to both sides
x^2 - 2x + 1 = -3/4 + 1
x^2 - 2x + 1 = 1/4
(x-1)^2 = 1/4
square root both sides x-1 = (+/-) 1/2
x1 = +1/2 + 1 = 3/2
x2 = -1/2 + 1 = 1/2
x-intercepts are 1/2 and 3/2, in form (3/2,0); (1/2,0)
The answer is 1.5 or 1 1/2.
here is the how you get this answer.
1: Cross Multiply (1.2)(60)=x
2: divide x by 48
3: you should get 1.5 or 3/2
BTW x is equal to 72
Answer:
A, 152 cm.
Step-by-step explanation:
A rectangular pyramid has a volume equation of
V = (lwh)/3.
Therefore, when we plug the values in:
[(7)(5)(13)]/3 = V
V = 455/3
V = 151.666667
V is approximately equal to 152 cm^3.
I hope this helped! :)
A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
6 outcomes -> 1, 2, 3, 4, 5, 6
But we want to find 4+
So:
4+ = 4, 5, 6
We also want to find all odd possibilities.
So:
odd = 1, 3, 5
As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6
So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%
Hope I helped!
Answer:
53
Step-by-step explanation:
70-17= 53
