All categories

3 years ago

2-An 83cm piece is cut from a length of ribbon measuring 1.3 metres. What length is left?

Mathematics

1 answer:

Delvig [45]3 years ago

3 0

Answer:

81.7cm is the length left behind

Step-by-step explanation:

83 -1.3 =81.7

You might be interested in

Nolan makes soup. He divides each batch equally into thirds to give away. Each family that he makes soup for gets 1 third of a b

Lorico [155]

1/3 for each family

5 families to have soup

So Nolan would need to make 2 batches of soup

8 0

3 years ago

Jill has a balance of $5,000 on her credit card with an annual interest rate of 15%. To pay off the $5,000 in three years, Jill

Simora [160]

Mark me brainlyest if i get this right 1 sec
 c is what it is

6 0

3 years ago

Read 2 more answers

Solve the equation. 42=d^2-22

ikadub [295]

The answer to question was to question it if you don’t answer your question about how you do that you have a question for you

4 0

3 years ago

Read 2 more answers

Line segment ON is perpendicular to line segment ML.

3241004551 [841]

Answer:

2 units.

Step-by-step explanation:

I just took the Unit Test.

6 0

3 years ago

Read 2 more answers

Rms/d/e/1FAIpQLSÜDABFGIUJs31xO8JDRug2175ehNYt_F-yaPG7RkyQmW5_puw/viewform?hr_submission=Chki-

geniusboy [140]

Answer:

12709 balls

Step-by-step explanation:

Given

Dimension of Room = 15 ft by 20 ft by 10 ft

Diameter of Ball = 9.2 inches

Required

Determine the number of balls that can be occupied by the room

First, we need to calculate the volume of the room

This is done by multiplying the dimensions of the room

$Volume = 15ft * 20ft * 10ft$

$Volume = 3000ft^3$

Next, we calculate the volume of the ball.

The ball is a sphere.

So:

$Volume = \frac{4}{3}\pi r^3$

Where

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * 9.2$

$r = 4.6\ in$

So:

$Volume = \frac{4}{3}\ * \frac{22}{7} * (4.6in)^3$

$Volume = 407.88419\ in^3$

To calculate the number of balls, we then divide the volume of the room by volume of a ball

$Balls = \frac{3000\ ft^3}{407.88419\ in^3}$

Convert ft^3 to in^3

$Balls = \frac{3000 * 1728in^3}{407.88419\ in^3}$

$Balls = \frac{3000 * 1728}{407.88419}$

$Balls = \frac{5184000}{407.88419}$

$Balls = 12709.4899167$

$Balls = 12709$ <em>-- approximated</em>

<em>Hence, the room will contain 12709 balls</em>

5 0

3 years ago