Question

A ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor. part a how long will it take the ball to hit the floor?

Answer 1

Working formula:

y = v*t + 0.5*a*t^2

where:
   y = vertical distance = -1 m
   v = initial velocity = 1.25m/s
   a = acceleration = 9.81 m/s^2
   t = time

Required: t

Solution:

y = v*t + 0.5*a*t^2
1 = (1.25)*t + 0.5*9.81*t^2
0 = -1 + 1.25t + 4.905t^2

Applying completing the square, we get
t = 0.342 s, - 0.597s

Technically, we don't have time with negative value. Thus, the answer is t = 0.342 seconds