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Brut [27]
3 years ago
5

Newton's first law of motion states that an object will keep a constant speed and direction unless acted upon by an unbalanced f

orce. To test this statement, Martin rolled a ball on a long, level street. The ball did not bump into any object, but it eventually came to a stop. How is this possible? Martin did not roll the ball hard enough, which caused the ball to eventually stop rolling. The unbalanced force that caused the ball to stop was friction. Every moving object must come to a stop because energy cannot be destroyed. Newton's first law of motion only holds true in space, not on Earth. Martin initially applied a force to the ball, which started the ball moving. After the ball left his hand, the force he applied was no longer there.
So we have this ball rolling, but instead of keeping its constant speed it comes to a stop! And according to Newton's first law, an object will keep a constant speed and direction unless acted upon by an unbalanced force. So if the ball comes to a stop, it has CHANGED its speed, right? So there must be an UNBALANCED force!

Our options:

1. Martin did not roll the ball hard enough
Well if he rolled it harder it would start out with a faster speed, but we know that it would eventually come to a stop.

2. The unbalanced force that caused the ball to stop was friction.
This makes sense. We know there is an unbalanced force on the ball, and friction happens to be a force that is always in the direction opposite of motion.

3. Every moving object must come to a stop because energy cannot be destroyed.
Energy cannot be destroyed, but it can be transferred! Perhaps the energy is transferred out of the ball through friction ;)

4. Newton's first law of motion only holds true in space, not on Earth
Newton's laws are universal! So you can apply them to Earth, space, other planets, etc. He was actually one of the first ones to make the connection between motion on Earth, and motion out in space. In the Newton-apple story (when he sees the apple fall from the tree), he wonders if the force (gravity) that pulls the apple to the ground on earth could reach out all the way out to other planets!

I hope this gives you a little bit of insight.
Physics
2 answers:
Kisachek [45]3 years ago
8 0
I think the correct answer from the choices listed above is option 2. The ball stop because there is an additional force that is present that causes it to be unbalanced. The unbalanced force that caused the ball to stop was friction.
This makes sense. We know there is an unbalanced force on the ball, and friction happens to be a force that is always in the direction opposite of motion. Hope this answers the question. Have a nice day.
trasher [3.6K]3 years ago
3 0

Answer:

The unbalanced force that caused the ball to stop was friction

Explanation:

As Newton's second law states, the acceleration of an object is proportional to the net force applied on the object:

F=ma

therefore, in order to move at constant speed, an object should have a net force of zero (balanced forces) acting on it.

In this case, the ball slows down and eventually comes to a stop: it means that the ball is decelerating, so there are unbalanced forces (net force different from zero) acting on it. The unbalanced force acting on the ball is the friction: friction is a force against the motion of the object, which is due to the contact between the surface of the ball and the surface of the street, and this force is responsible for slowing down the ball.

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Answer:

The angular acceleration of the pencil<em> α  = 17 rad·s⁻²</em>

Explanation:

Using Newton's second angular law or torque to find angular acceleration, we get the following expressions:

    τ = I α                              (1)

    W r = I α                          (2)

The weight is that the pencil has is,

   sin 10 = r / (L/2)

   r = L/2(sin(10))

 

The shape of the pencil can be approximated to be a cylinder that rotates on one end and therefore its moment of inertia will be:

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Thus,

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3 years ago
a 700k/g race car slowed down from 30m/s to 15m/s what is the impulse and what was the average force applied by the brakes
posledela
So impulse is a change in momentum.

Mass*(final velocity - initial velocity)

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3 years ago
A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i
attashe74 [19]

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>
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  • U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

  • So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>
  • As per Newton's equation of motion,

V²-U² = 2aS

  • S= distance covered by the car
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=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

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You are helping two friends from our class with a physics problem where a cart is pushed up a ramp. In examining the motion of t
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Answer: Acceleration will have 2 components, vertical and horizontal.

Net-vertical component can be positive, zero or negative depending upon the magnitude of the upward component of the applied acceleration.

Net-horizontal acceleration will  be equal to the horizontal component of the applied acceleration.

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Since acceleration is a vector quantity and the cart is being pushed up the ramp, the ramp would be at some angle to the horizontal and hence there will be vertical and horizontal components of acceleration.

<u>For vertical acceleration:</u>

If the magnitude of the upward component of the applied acceleration is greater than the value of the acceleration due to gravity then the net vertical acceleration will be upward because it will overtake the value of acceleration due to gravity.

In case the upward component of the applied acceleration is lesser than the value of the acceleration due to gravity then the net vertical acceleration will be downward.

<u>For horizontal acceleration:</u>

This component remains unaffected and is equal to the horizontal component of the applied acceleration because there is no other acceleration acting in the horizontal direction.

But the net acceleration will not be solely in the vertical or horizontal direction because the block has to move forward on the inclined ramp so there will always exist a horizontal and a vertical component making the net acceleration to parallel to the ramp in upward direction if the body is going up the ramp.

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Answer:

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