The tiger's position at time <em>t</em> is given by
<em>x</em> (horizontal) = (4.5 m/s) <em>t</em>
<em>y</em> (vertical) = 7.5 m - 1/2 <em>gt</em> ²
Solve <em>y</em> = 0 for <em>t</em> to find the time it takes for the tiger to reach the ground :
0 = 7.5 m - 1/2 (9.8 m/s²) <em>t</em> ²
===> <em>t</em> = √(2 (7.5 m) / (9.8 m/s²)) ≈ 1.2 s
Evaluate <em>x</em> at this time :
<em>x</em> = (4.5 m/s) (1.2 s) ≈ 5.6 m
