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spayn [35]
3 years ago
9

The measure of one of the acute angles in a right triangle is 42 1/3 . What is the measure of the other acute angle in the trian

gle?
Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0
Explanation: The sum<span> of the measure of the </span>internal<span> angles of any triangle is 180o . In a right angled triangle, one angle will be 90o . Since we know the measure of one of the other acute (less than 90o ) angles, we subtract the </span>sum<span> of the two known angles from 180 to calculate the measure of the other acute angle.</span>
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x=5 and y=8

Step-by-step explanation:

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----   ----

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P is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin O to P, is a minimum. Find the
nirvana33 [79]
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span>                                      =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x 
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<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2)   (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
 
Then y = 10 - 2(4) = 2.
 So the point, P, is (4,2).
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3 years ago
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