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Lubov Fominskaja [6]
3 years ago
12

Mr. pope lost 10 pounds in one month. At the end of the month, he weighed 240 pounds. By what percentage did Mr. Pope decrease h

e weight?
a. (4%)
b. (7%)
c.(10)
d.(15%)
Mathematics
1 answer:
Yuri [45]3 years ago
8 0
The answer for this question would be a which is 4% and hopefully you get it right
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Given
Sergeu [11.5K]

Answer:option 2

Step-by-step explanation:sets Band C contains 2,4,6 in common

Set A and the common set of B and C stated above contains 2 in common

7 0
3 years ago
I need help ASAP!!Please explain how to solve the problem
rjkz [21]

Answer:

( x - 2 )^2 + ( y - 1 )^2 = 1

Step-by-step explanation:

As i previously explained,

The general form of equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2.

h and k are the co-ordinates of the center of circle and r is the radius

Here, We have (2,1) as the co-ordinates of the center of circle

Now,

( x - h )^2 + ( y - k )^2 = r^2

or,( x - 2 )^2 + ( y - 1 )^2 = r^2

The radius of the circle is 1 units(from figure)

So, put that in, we get

( x - 2 )^2 + ( y - 1 )^2 = 1^2

or, ( x - 2 )^2 + ( y - 1 )^2 = 1

You can simplify this or leave it here.

8 0
3 years ago
On a manufacturer's assembly line, 3% of its merchandise comes off defective. If the company has 354 defective items, how many t
Rainbow [258]
3% of x = 354 <span>3%∗<span>1<span>100%</span></span>∗x=354</span><span><span><span>3x</span>100</span>=354</span>Can you solve that for x<span>?</span>
8 0
3 years ago
Read 2 more answers
Apply The Remainder Theorem, Fundamental Theorem, Rational Root Theorem, Descartes Rule, and Factor Theorem to find the remainde
Over [174]

9514 1404 393

Answer:

  possible rational roots: ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12}

  actual roots: -1, (2 ±4i√2)/3

  no turning points; no local extrema

  end behavior is same-sign as x-value end-behavior

Step-by-step explanation:

The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.

The Rational Root Theorem tells us any rational roots will be of the form ...

  ±{factor of 12}/{factor of 3} = ±{1, 2, 3, 4, 6, 12}/{1, 3}

  = ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12} . . . possible rational roots

Descartes' Rule of Signs tells us the two sign changes mean there will be 0 or 2 positive real roots. Changing signs on the odd-degree terms makes the sign-change count go to 1, so we know there is one negative real root.

The y-intercept is 12. The sum of all coefficients is 22, so f(1) > f(0) and there are no positive real roots in the interval [0, 1]. Synthetic division by x-1 shows the remainder is 22 (which we knew) and all the quotient coefficients are all positive. This means x=0 is an upper bound on the real roots.

The sum of odd-degree coefficients is 3+8=11, equal to the sum of even-degree coefficients, -1+12=11. This means that -1 is a real root. Synthetic division by x+1 shows the remainder is zero (which we knew) and the quotient coefficients alternate signs. This means x=-1 is a lower bound on real roots. The quotient of 3x^2 -4x +12 is a quadratic factor of f(x):

  f(x) = (x +1)(3x^2 -4x +12)

The complex roots of the quadratic can be found using the quadratic formula:

  x = (-(-4) ±√((-4)^2 -4(3)(12)))/(2(3)) = (4 ± √-128)/6

  x = (2 ± 4i√2)/3 . . . . complex roots

__

The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.

4 0
3 years ago
My math final please help
spin [16.1K]

Answer:

m∠3 = 56

Step-by-step explanation:

Let's solve for x, first:

x + 9 = 3x - 85

9 = 2x - 85

94 = 2x

94/2 = x

47 = x

Now that we have x-value, we can substitute it in any one of the given equation to find angle 3 since, angle 1, 7 and 3 all are congruent:

=> m∠7 = x + 9

=> m∠7 = 47 + 9

=> m∠7 = 56

Since m∠7 ≅ m∠3

and m∠7 = 56, then

<u>m∠3 = 56</u>

Hope this helps!

6 0
3 years ago
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