Answer:
(a)Revenue function,
Marginal Revenue function, R'(x)=580-2x
(b)Fixed cost =900
.
Marginal Cost Function=300+50x
(c)Profit,![P(x)=-35x^2+280x-900](https://tex.z-dn.net/?f=P%28x%29%3D-35x%5E2%2B280x-900)
(d)x=4
Step-by-step explanation:
<u>Part A
</u>
Price Function![= 580 - 10x](https://tex.z-dn.net/?f=%3D%20580%20-%2010x)
The revenue function
![R(x)=x\cdot (580-10x)\\R(x)=580x-x^2](https://tex.z-dn.net/?f=R%28x%29%3Dx%5Ccdot%20%28580-10x%29%5C%5CR%28x%29%3D580x-x%5E2)
The marginal revenue function
![\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x](https://tex.z-dn.net/?f=%5Cdfrac%7BdR%7D%7Bdx%7D%3D%20%5Cdfrac%7Bd%7D%7Bdx%7D%28R%28x%29%29%3D%5Cdfrac%7Bd%7D%7Bdx%7D%28580x-x%5E2%29%3D580-2x%5C%5CR%27%28x%29%3D580-2x)
<u>Part B
</u>
<u>(Fixed Cost)</u>
The total cost function of the company is given by ![c=(30+5x)^2](https://tex.z-dn.net/?f=c%3D%2830%2B5x%29%5E2)
We expand the expression
![(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2](https://tex.z-dn.net/?f=%2830%2B5x%29%5E2%3D%2830%2B5x%29%2830%2B5x%29%3D900%2B300x%2B25x%5E2)
Therefore, the fixed cost is 900
.
<u>
Marginal Cost Function</u>
If ![c=900+300x+25x^2](https://tex.z-dn.net/?f=c%3D900%2B300x%2B25x%5E2)
Marginal Cost Function, ![\frac{dc}{dx}= (900+300x+25x^2)'=300+50x](https://tex.z-dn.net/?f=%5Cfrac%7Bdc%7D%7Bdx%7D%3D%20%28900%2B300x%2B25x%5E2%29%27%3D300%2B50x)
<u>Part C
</u>
<u>Profit Function
</u>
Profit=Revenue -Total cost
![580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900](https://tex.z-dn.net/?f=580x-10x%5E2-%28900%2B300x%2B25x%5E2%29%5C%5C580x-10x%5E2-900-300x-25x%5E2%5C%5C%24Profit%2CP%28x%29%3D-35x%5E2%2B280x-900)
<u>
Part D
</u>
To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.
![P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4](https://tex.z-dn.net/?f=P%28x%29%3D-35x%5E2%2B280x-900%5C%5CP%27%28x%29%3D-70x%2B280%5C%5C-70x%2B280%3D0%5C%5C-70x%3D-280%5C%5C%24Divide%20both%20sides%20by%20-70%5C%5Cx%3D4)
The number of cakes that maximizes profit is 4.
Answer: 4.2 lbs
Step-by-step explanation:
Amount of grapes he had (in pounds) = 1.9 + 2.3 pounds
Amount of grapes he had (in pounds) = 4.2 pounds
Answer:
you put the -3 where the x's are
Step-by-step explanation:
f(x)= -2(-3)^2 - 3(-3) + 6
i think i hope thats right
Answer:
x = 0
Step-by-step explanation:
Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2.
H - head
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T) = 0.8
urn
3 red and 5 blue
when heads is obtained
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12
when tails is obtained
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3
using bayes rule the answer can be found out,
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
= 0.12 / (0.12 + 0.3)
= 0.12 / 0.42
= 0.286
the final answer is 0.286