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baherus [9]
2 years ago
7

What is the distance between the points? Round to the nearest tenth if necessary.

Mathematics
2 answers:
Svetlanka [38]2 years ago
8 0

Answer:

1.7

Step-by-step explanation:

You do rise over run or y/x to find your answer. You go over 6 and up 10 to get from the lower point to the one on top. 10/6=1.666667 and rounded will be 1.7

dlinn [17]2 years ago
3 0

Answer:

i say D. 11.7

Step-by-step explanation:

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myrzilka [38]

Answer:

A Subtract 87 from 271 and then divide the

difference by 5.75

Step-by-step explanation:

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2 years ago
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PLEASE HELP GUYS THANK YOU IN ADVANCED
VikaD [51]

Answer:

x=3.5

Step-by-step explanation:

6 0
3 years ago
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Last year, the mean running time for a certain type of light bulb was 8.5 hours. This year, the manufacturer has introduced a ch
Free_Kalibri [48]

Answer:

H0 : μ = 8.5

H1 : μ > 8.5

1 sample t test ;

Test statistic = 2.53

Pvalue = 0.994

No, we fail to reject the Null ;

There is no significant evidence to support the Claim that the mean running time of light bulb is greater Tha last year.

Step-by-step explanation:

H0 : μ = 8.5

H1 : μ > 8.5

Test statistic :

(xbar - μ) ÷ (s/sqrt(n))

(8.7 - 8.5) ÷ (0.5 / sqrt40)

Test statistic = 2.53

The Pvalue :

P(Z < 2.53) = 0.9943

Pvalue = 0.994

Decison region :

Reject H0 ; if Pvalue < α

0.9943 > 0.05 ; We fail to reject the Null

5 0
3 years ago
A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
3x + 40 = 11x -24<br><br> What does x equal?
pogonyaev
First, you would have to do 11x + 3x Since you're combining like terms.

Now your problem is 14x + 40 = -24

Now you would do 40 - -24 which is now 40+24 and equal to 64.

Now you divide 14 by 64 and you get 4.5
4 0
3 years ago
Read 2 more answers
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