The <u>possible rational zeros</u> of <u>polynomial function</u> 
could be only among the <u>divisors</u> of the <u>free term</u> of this polynomial function.
The free term is 20 and the divisors of 20 are:
Answer: correct choice is C
All you have to do is try out both of the equations with each of the different choices.
200 = 45 (3) + 20
200 = 135 + 20
200 = 155
200 = 35 (3) + 60
200 = 105 + 60
200 = 165
So, this one does not work.
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180 = 45 (3) + 20
180 = 135 + 20
180 = 155
180 = 35 (3) + 60
180 = 105 + 60
180 = 165
So, this one does not work.
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200 = 45 (4) + 20
200 = 180 + 20
200 = 200
200 = 35 (4) + 60
200 = 140 + 60
200 = 200
So this one works.
The answer would be C.
I hope this helps and I'm sorry it took so long!
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
4A = E , A=E/4-----(1)
B/4=E , B=4E-------(2)
C+4=E, C=E-4------(3)
D-4=E, D=E+4------(4)
Substitute all values in 5th equation,
A+B+C+D=100 = E/4 + 4E + E-4+ E+4 =100
E/4 + 6E = 100
25E = 400
E=16 ANS....
Answer:
:)
Step-by-step explanation:
It's B . carmel.bratz go add the snap
