The morality, molality, and mole fraction of NaOH is mathematically given as
- morality= 4 ppm
- molality=0.7936m
- x1 = 0.152
What are the morality, molality, and mole fraction of NaOH?
Question Parameters:
A solution was made by dissolving 800. 0 g of NaOH in 25,200 g of water.
Generally, the equation for the Molality is mathematically given as
molality = (mass / molar mass) x (1/ weight of solvent kg)
Therefore
M= (800 /40) x (1 /25.2)
M=0.7936m
Therefore
m= 10 x 18 / 1000
m= 0.18
Hence
x1 = 0.18 - 0.18 x1
1.18 x1 = 0.18
x1 = 0.152
Where the mole fraction is x1 = 0.152 The mass is
m= (800 / 800 + 2000) x 1000
m= 28.57 %
Hence the morality
molality = mg /L
molality= 8000 x 10^-3 / 2 L
morality= 4 ppm
In conclusion, the morality, molality, and mole fraction of NaOH are given respectively as
morality= 4 ppm
molality=0.7936m
x1 = 0.152
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Answer:
correct option is a. common costs
Explanation:
solution
As common costs are those associated with operating a facility shared by the two departments
and here One facility located in Iowa and corn from the facility will be more further process into the corn for popping and the cornmeal
so as given cost at given costs at Iowa plant is common costs
so correct option is a. common costs
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