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2 years ago

Match the equations of the lines with their graphs.

Mathematics

1 answer:

xxMikexx [17]2 years ago

3 0

Answer:

Step-by-step explanation:

1. y=2x-3

2. y=2x+3

3. y=-2x+3

4. y=-2x-3

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7. Compare the value of the 5 in 85,327 and 435.

Colt1911 [192]

Answer:

5 in the 85327= five thousand units

5 in the 435= five units

Step-by-step explanation:

85,327= eighty five thousand, three hundred and twenty seven

Value of five or the position if five in the above number is the thousand position

5 in the above = five thousand unit

435= four hundred and thirty five

The position of five in the above number is the unit position

Five in the above= five unit

6 0

3 years ago

cyclists were 3/5 finished with their ride when they reached the 15 kilometer mark how long was the ride

butalik [34]

3/5 of the ride = 15 km

1/5 of the ride = 15 ÷ 3 = 5km

5/5 of the ride = 5 x 5 = 25km

Answer: the ride is 25km

4 0

2 years ago

Read 2 more answers

15 POINTS

mafiozo [28]

B i would say I'm sure

7 0

2 years ago

Read 2 more answers

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

2 years ago

100 POINTS!!!!!!!!!!

Ne4ueva [31]

the fiest answer is x=6 for the second one the answer is x=4

Step-by-step explanation:

x+15/5x+1 =15/35 then cross multiply

1st one

5 0

2 years ago

Read 2 more answers