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3 years ago

I need to know how to do it in Distributive Property.

Mathematics

1 answer:

kotykmax [81]3 years ago

6 0

A(b-c)=ab-ac

(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14

now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h

You might be interested in

Please can i have some with the question attached thanks.

ozzi

Answer:

13/6

Step-by-step explanation:

6/13 * x = 1

Multiply each side by 13/6

6/13 * 1/3 6 * x = 1 * 13/6

x = 13/6

7 0

3 years ago

Write and solve a proportion to answer the question.

andreev551 [17]

Number 1 is 1/20 ,so number 0.5 is 1/40 of 20. so p=100/40 = 10/4 = 2.5%
so 0.5 is 2.5% of 20
proof: 2.5*20/100 =50/100 = 0.5

5 0

3 years ago

A stand is a frustum shape, formed by removing a small square-based pyramid from the top of

kupik [55]

The frustum can be considered as consisting of a square pyramid, less the

cut volume.

The mass of the stand, is approximately 18.60905 kg

Reasons:

The given parameter of the frustum are;

The density of the frustum, ρ = 85 g/cm³

Height of pyramid, h = 9 cm

Side length of base = 10 cm

Height of frustum

By proportional shapes, the side length of the top of the frustum can be found as follows;

$\dfrac{4 \, cm}{9 \, cm} = \dfrac{x}{10 \, cm}$

$x = \dfrac{4 \, cm}{9 \, cm} \times 10 \, cm = 4\frac{4}{9} \, cm$

$V = \dfrac{h}{3} \times \left(B_1 + B_2 + \sqrt{B_1 \times B_2} \right)$

B₁ = 10², B₂ = $\left(4\frac{4}{9} \right)^2$

Therefore;

$V = \dfrac{4}{3} \times \left(10^2 + \left(4\frac{4}{9} \right)^2 + \sqrt{10^2 \times \left(4\frac{4}{9} \right)^2} \right) \approx 218.93$

The volume of the stand, V ≈ 218.93 cm³

Mass = Volume × Density

∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.

Learn more here:

brainly.com/question/24323975

8 0

2 years ago

In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma

bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a) $=\frac{v-u}{t}$

$a=\frac{60\times 60\times 60}{4}$

$a=54\times 10^3 mi/h^2$

To reach a speed of 183.58mi/h with an acceleration of $54\times 10^3 mi/h^2$

Using equation of motion

v=u+at

$183.58=0+(54\times 10^3)t$

$t=\frac{183.58}{54\times 10^3}$

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

$s=ut+\frac{1}{2}at^2$

$5=0+\frac{1}{2}\times 54\times 10^3 \times t^2$

t=0.01360 hour

or $t=48.98\approx 49 s$

7 0

3 years ago

The janitor at a school discovered a leak in a pipe. The janitor found that it was leaking at a rate of 11 fl oz per hour. How f

netineya [11]

Here's what you need to know in order to answer this:

   1 gallon = 128 fl oz
and
   1 day = 24 hours.

Use those facts to invent fractions equal to ' 1 '.
Then use those to change the units of the "11 fl oz per hour".
You can multiply them ... since their value is ' 1 ', they won't
change the value of the "11 fl oz per hour", only the units.

(11 fl oz/hr) x (24 hr/da) x (1 gal / 128 fl oz)

   = (11 x 24 x 1 / 128) (fl-oz - hr - gal) / (hr - da - fl-oz)

   =     2.0625    gal/da

6 0

3 years ago