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3 years ago

I need to know how to do it in Distributive Property.

Mathematics

1 answer:

kotykmax [81]3 years ago

6 0

A(b-c)=ab-ac

(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14

now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h

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one positive number is 12 times another positive number. The difference between the two numbers is 143

Natali [406]

Let x be the unknown number and let's set up an equation.
12x - x = 143
Now solve for x:
11x = 143
x = 13
The positive number is 13.

5 0

3 years ago

Read 2 more answers

I don't get this one too can someone explain it please

lukranit [14]

Answer:

15ab

Step-by-step explanation:

When you multiply out the square (p+q)^2, you get the trinomial ...

(p +q)^2 = p^2 + 2pq + q^2

Your binomial is (3a+2.5b), so you have ...

p = 3a

q = 2.5b

and the trinomial you get when you multiply it out is ...

(3a)^2 + 2(3a)(2.5b) + (2.5b)^2

= 9a^2 + 15ab + 6.25b^2

The first and last of these terms are shown on the right side of the given expression, so to finish out the identity, you need to replace * with 15ab.

5 0

3 years ago

Need help on this test fast

vfiekz [6]

Answer:

Step-by-step explanation:

6 0

3 years ago

The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the

Degger [83]

Using the normal distribution, we have that:

The distribution of X is $X \approx (57,22)$ .

The distribution of $\mathbf{\bar{X}}$ is $\bar{X} \approx (57, 5.3358)$ .

0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem, the parameters are given as follows:

$\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358$

Hence:

The distribution of X is $X \approx (57,22)$ .

The distribution of $\mathbf{\bar{X}}$ is $\bar{X} \approx (57, 5.3358)$ .

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{58 - 57}{22}$

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{55 - 57}{22}$

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

$Z = \frac{X - \mu}{s}$

$Z = \frac{58 - 57}{5.3358}$

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

$Z = \frac{X - \mu}{s}$

$Z = \frac{55 - 57}{5.3358}$

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0

1 year ago

The total cost of a jacket and a pair of shoes was $52.95. If the price of the jacket was $3.87 less than the pair of shoes, wha

abruzzese [7]

The price of jacket was $24.54

Step-by-step explanation:

Let,

Cost of jacket = x

Cost of pair of shoes = y

According to given statement;

x+y=52.95 Eqn 1

x = y-3.87 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$(y-3.87)+y=52.95\\y-3.87+y=52.95\\2y=52.95+3.87\\2y=56.82\\$

Dividing both sides by 2

$\frac{2y}{2}=\frac{56.82}{2}\\y=28.41$

Putting y=28.41 in Eqn 2,

$x=28.41-3.87\\x=24.54$

The price of jacket was $24.54

Keywords: linear equation, division

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago