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Komok [63]
3 years ago
10

I need to know how to do it in Distributive Property.

Mathematics
1 answer:
kotykmax [81]3 years ago
6 0
A(b-c)=ab-ac

(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14

now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h

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hodyreva [135]

Answer:

f(-4) = -5

Step-by-step explanation:

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3 years ago
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7. Solve the equation using the quadratic formula.<br> 3x^2 = 2(2x+1)
suter [353]

Answer:

\rm x = \dfrac{2+\sqrt{10}}{3},\dfrac{2-\sqrt{10}}{3}

Step-by-step explanation:

A quadratic equation is given to us and we need to solve the equation using the quadratic formula . The given equation is ,

\rm\implies 3x^2=2(2x+1)

Open the brackets in RHS ,

\rm\implies 3x^2= 4x + 2

Transpose all the terms to LHS ,

\rm\implies 3x^2-4x-2=0

The general form of a quadratic equation is ax² + bx + c = 0 , and the roots of the equation by the Quadratic Formula ( Shreedhacharya's Formula ) is given by ,

\rm\implies\red{ x =\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}

Using the quadratic formula , we have ,

\rm\implies x =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(3)(-2) }}{2(3)}

Simplify ,

\rm\implies x =\dfrac{4 \pm \sqrt{16+24 }}{6}

\rm\implies x = \dfrac{4\pm \sqrt{40}}{6}

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\rm\implies\boxed{\pink{\frak{ x = \dfrac{2+\sqrt{10}}{3},\dfrac{2-\sqrt{10}}{3}}}}

8 0
2 years ago
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60 days.

Step-by-step explanation:

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Simply again:

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Subtract 6x from both sides:

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Option A, or x = 12

-T.B.

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