Here you are giving only the amount they want to raise (namely profit times number of magazines sold), and here you are also giving Money they want to raise... So clarifying, the money they want to raise, should include the money they will spend on buying the magazines (there is no statement saying they found them, or were given the magazines, so a cost should be involved)
Now if they are only making the count of "Field trip costs X amount of money, and given we have to make a profit of $5.5, How many must we sell?" then the equation should be n=X/5.5
Should the story be, how much money must they raise to have a profit of 5.5 on each magazine and still have enough for the field trip, then you have a different equation which varies only in adding the cost of each magazine, either case, M should be defined not as money they need to raise (cause here they will be short on their goal) but Money they must earn. And again, you should rewrite your equation to be:
M=Amount they must raise
C=Cost per magazine
n=Number of magazines
p=profit $5.5 per magazine
C+p=M/n
And rewriting the previous they should make:
n(C+p)=M -----> n(C+5.5)=M <span>m/n = 5.50 </span>
<span>m/n x n = 5.50 x n //// multiply each side by n </span>
<span>m = 5.5n</span>
Answer:
the term is separated by minus (-) and plus (+) .
therefore this term is trinomial.
So, the shortest side is 13, the other two fellows are two consecutive values.... ok... let's say the other leg is "a", a consecutive value to that will be a+1, so the hypotenuse is "a + 1" then
check the picture below
and surely you'd know what "a" is
Answer:
a) 
b) 
c) 
d) 
e) The intersection between the set A and B is the element c so then we have this:
Step-by-step explanation:
We have the following space provided:
![S= [a,b,c,d,e]](https://tex.z-dn.net/?f=%20S%3D%20%5Ba%2Cb%2Cc%2Cd%2Ce%5D)
With the following probabilities:
And we define the following events:
A= [a,b,c], B=[c,d,e]
For this case we can find the individual probabilities for A and B like this:
Determine:
a. P(A)
b. P(B)
c. P(A’)
From definition of complement we have this:
d. P(AUB)
Using the total law of probability we got:
For this case , so if we replace we got:
e. P(AnB)
The intersection between the set A and B is the element c so then we have this:
