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Reptile [31]
4 years ago
5

Pls help answer the question in the picture attatched!

Mathematics
1 answer:
sergejj [24]4 years ago
8 0

Answer:

N27W

Step-by-step explanation:

Add vectors

w = u+v = <-4,3>+<1,3> = <-3,6>

Cartesian Direction

theta = atan(6,-3)  (second quadrant) = 180-63.4 degrees = 116.6 degrees

Bearing = 90-theta = -26.6 degrees from north = N26.6W

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Two firms play the game below. Each must choose strategy 1 or 2. They choose their strategies simultaneously and without coopera
Lilit [14]

Answer:

B. Strategy 2 is a dominant strategy

Step-by-step explanation:

A strategy can be considered a dominant strategy for a player if that player gets the best payoff yields no matter what strategies the other players choose. Going by the question, Firm A getting an overall payoff of 30 from Strategy 2 as compared to 18 from  Strategy 1.

Therefore Strategy 2 is a dominant strategy

3 0
3 years ago
Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequal
sashaice [31]

Answer:

Step-by-step explanation:

a)

\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx

this can be done by substitute lnx = u

dx/x = du

When x =1, u =0 and when x =2, u = ln 2

So integral = \int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}

We find that this integral value is not definid for p =1

Hence for values of p other than 1, this converges.

When we substitute limits

\frac{1}{1-p} ((ln2)^{1-p} -1)

and converges for p ≠1

b) \int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C

So not converging for p =1

But ln x is defined only for x >0

So integral 0 to 1 makes this integral not valid and hence not convergent.

7 0
4 years ago
Solve for y in the following equation.
Tju [1.3M]

Answer:

y = \frac{z^2 - x}{2}

Step-by-step explanation:

Given:

\sqrt{x + 2y} = z

Required:

Solve for y (make y the subject of the formula)

SOLUTION:

\sqrt{x + 2y} = z

Square both sides

(\sqrt{x + 2y})^2 = z^2

x + 2y = z^2

Subtract both sides by x

2y = z^2 - x

Divide both sides by 2

y = \frac{z^2 - x}{2}

5 0
3 years ago
How do you reflect point (4,-6) on the x-axis and then on the y-axis
stepan [7]

Answer:

(-4,6)

Step-by-step explanation:

When you reflect a point across the x and then y-axis, it is called an Origin Reflection

Origin Reflections, to put it simply, is when you have two points (a,b) and you find their opposites (-a,-b)

You have the point (4,-6)

The origin reflection of this point is (-4,6)!

3 0
4 years ago
3 4/5 - 2 1/3 and if needed simplify
Annette [7]
1 7/15 hopes this works
8 0
3 years ago
Read 2 more answers
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