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3 years ago

14

John had 2/3 of his homework complete, Sarah had 5/10, Alex 7/8, and Michelle 1/2. Who competed the most of the homework assignm

ent
A) Michelle
B) Sarah
C) John
D) Alex

2 answers:

ozzi3 years ago

7 0

Alex definitely had the most work done between all of them

adelina 88 [10]3 years ago

7 0

The correct answer is alex

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Step-by-step explanation:

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4 years ago

Given s left parenthesis t right parenthesis equals 5 t squared plus 5 ts(t)=5t2+5t, find

finlep [7]

Answer:

The velocity function is $v(t)=10t+5$ .

The acceleration function is $a(t)=10$ .

When t = 44, the velocity is $v(44)=445 \:\frac{ft}{s}$ .

When t = 44, the acceleration is $a(44)=10\: \frac{ft}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=5t^2+5t$

Velocity is defined as the rate of change of position or the rate of displacement. If you take the derivative of the position function you get the instantaneous velocity function.

$v(t)=\frac{ds}{dt}$

Acceleration is defined as the rate of change of velocity. If you take the derivative of the instantaneous velocity function you get the instantaneous acceleration function.

$a(t)=\frac{dv}{dt}$

The instantaneous velocity function is given by

$v(t)=\frac{d}{dt} s(t)=\frac{d}{dt}(5t^2+5t)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(5t^2\right)+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\v(t)=10t+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dt}\left(t\right)=1\\\\v(t)=10t+5$

The instantaneous acceleration function is given by

$a(t)=\frac{dv}{dt} =\frac{d}{dt}(10t+5)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\a(t)=\frac{d}{dt}\left(10t\right)+\frac{d}{dt}\left(5\right)\\\\a(t)=10$

To find the velocity and acceleration when t = 44, we substitute this value into the velocity and acceleration functions

$v(44)=10(44)+5\\v(44)=445 \:\frac{ft}{s}$

$a(44)=10\: \frac{ft}{s^2}$

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4 years ago

In a certain triangle x,y,z represents side lengths if x=7 and z=5 what must be true about y

irga5000 [103]

Answer:

$2 < y < 12$

Step-by-step explanation:

Given

$x = 7$

$z = 5$

Required

What must be true about y?

To answer this, we first calculate the range as follows;

$Minimum = |x - z|$

and

$Maximum = |x + z|$

For Minimum, we have:

$Minimum = |7 - 5|$

$Minimum = |2|$

$Minimum = 2$

For Maximum, we have:

$Maximum = |7 + 5|$

$Maximum = |12|$

$Maximum = 12$

The values of y are then bounded by the following:

$Minimum < y < Maximum$

This gives

$2 < y < 12$

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3 years ago