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antoniya [11.8K]
3 years ago
5

Which characteristic of data requires that the variables and data values be defined at the lowest (or as low as required) level

of detail for the intended use of the data?
Mathematics
2 answers:
Rudiy273 years ago
7 0

Answer:

data granularity

Step-by-step explanation:

Granular data is a type of data that are in pieces, they are data which exists at the lowest possible size so that it can be detailed and definite. Granular data can be joined with other external data source and is easily managed. It can be used for data analysis because it is definite and detailed.

Data granularity helps businesses in making decisions based on the analysis reported. It also helps businesses to check their performance and make adjustments that cam improve their sales and thus income.

sweet [91]3 years ago
3 0

Answer:

Data granularity

Step-by-step explanation:

Granularity of data refers to the level of detail of your data within the data structure. The higher/ finer your granularity is, the more data you have to store (of course with more detail). To aggregate data you obviously need the same granularity. And granularity will determine what kind of information (reports, etc.) you can create/ get out of your database.

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If 3% of ties sold in the United States are bow ties, what is the probability of randomly selecting three ties that were purchas
Luda [366]
Given that 3 ties were selected and the probability of selecting a bow tie is 3%, the probability of selecting 3 bow ties will be:
P(selecting 3 ties)=P(selecting a bow tie)*P(selecting a bow tie)*P(selecting a bow tie)
=(0.03)*(0.03)*(0.03)
=0.000027
7 0
4 years ago
How do I draw and determine the equation of a trend line on a scatterplot
Nat2105 [25]

Step-by-step explanation:

Step 1: Draw your trend line.

You begin by drawing your trend line. You want your trend line to follow your data. You want to have roughly half your data above the line and the other half below the line, like this:

trend line equation

Step 2: Locate two points on the line.

Your next step is to locate two points on the trend line. Look carefully at your trend line and look for two easy to figure out points on the line. Ideally, these are points where the trend line crosses a clearly identifiable location.

For the trend line that we just drew, we can see these two easily identifiable points.

trend line equation

We can easily identify these two points as (3, 3) and (12, 6).

Step 3: Plug these two points into the formula for slope.

The formula for slope is this one:

trend line equation

We can label our first point as (x1,y1), and our second point as (x2,y2). So our x1 is 3, our y1 is 3, our x2 is 12, and our y2 is 6. Plugging these values into the equation for slope and evaluating, we get this:

trend line equation

So our slope is 1/3.

8 0
3 years ago
Sarita showed the steps to solving the equation.
shtirl [24]

The option that explains Sarita's mistake is Sarita’s solution is correct. She made an error in her verification.

<h3>What was Sarita's mistake?</h3>

The given equation is: 5(x - 3) + 7(x + 4) = 73

In order to determine the value of x, take the following steps:

1. Apply the Distributive property:

5x - 15 + 7x + 28 = 73

2. Add similar terms together:

12x  + 13 = 73

3. Combine similar terms:

12x = 73 - 13

4. Add similar terms

12x = 60

5. Divide both sides of the equation by 12

x = 60 / 12

x = 5

In order to verify the answer, substitute for x in the given equation :

5(5 - 3) + 7(5 + 4) = 73

5(2) + 7(9) = 73

10 + 63 = 73

73 = 73

Please find attached the complete question. To learn more about equations, please check: brainly.com/question/14446120

#SPJ1

6 0
1 year ago
Ed spoke to his cousin in Australia, who told him it was 28 degrees Celsius that day. Ed wasn’t sure if that was hot or cold, so
Allisa [31]

Answer:

82

Step-by-step explanation:

Do the equation

6 0
3 years ago
Read 2 more answers
In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu
olya-2409 [2.1K]

Answer:

19.6-2.42\frac{5.8}{\sqrt{42}}=17.43    

19.6+2.42\frac{5.8}{\sqrt{42}}=21.77    

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

\bar X= 19.6 represent the sample mean

\mu population mean

\sigma= 5.8 represent the population deviation

n=42 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.98 or 98%, the significance would be \alpha=0.02 and \alpha/2 =0.1, and the critical value would be t_{\alpha/2}=2.42

Replacing we got:

19.6-2.42\frac{5.8}{\sqrt{42}}=17.43    

19.6+2.42\frac{5.8}{\sqrt{42}}=21.77    

And the best option for this case would be:

a. (17.5, 21.7)

8 0
3 years ago
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