Answer:
a. Parallel
b. Not parallel
Step-by-step explanation:
Systems which have no solutions are parallel lines. These lines do not intersect and therefore have no solution. Remember, parallel lines have the same slope. Compare the slope in each equation when in y=mx+b format to see if they are parallel.
a. y= 2x + 3 y-2x=-3 becomes y = 2x - 3
m = 2 m= 2
The slopes are the same so these are parallel lines.
b. 3x + y = 2 becomes y= -3x + 2 y = 1/3 x + 1/2
m = -3 m= 1/3
The slopes are different so this is not parallel.
Since -3 and 1/3 are the negative reciprocals of each other. These lines are actually perpendicular.
Answer:
10
Step-by-step explanation:
x+x+2+x+4=24
3x+6 = 24
x=6
x+4=10
<span>It is clear to see that 0.0259 is less than 0.05. A p-value that is less than the confidence level of alpha indicates that there is sufficient evidence from the data that the null hypothesis should be rejected in favor of an alternative hypothesis.</span>
Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE