Answer:
firewall
Explanation:
The firewall could be used to protect the network from unauthorised access.Usually an ip could be whitelisted so it could transfer packets between allowing it connect through.
Answer:These are your answers
B.) Type a paragraph.
C.) Take notes for social studies class.
D.) Edit a paragraph.
Explanation:
Typing an paragraph can be able to be used in an word processor because he can fix grammatical errors.
All the the answer choices I picked can be processed through an word processor Because they all are created using words.
Answer:
to be effectively computable, the person is definite, explicit and 'mechanical'.
Answer:
The program in Python is as follows:
print("Enter a character followed by a phrase",end='')
word = input(": ")
char = word[0]
print("Occurrence: "+str((word.count(char))-1))
Explanation:
The prints an instruction to the user on how to input to the system
print("Enter a character followed by a phrase",end='')
This prompts and gets the user for input
word = input(": ")
This extracts the character from the input string
char = word[0]
This counts and prints the number of occurrence of the extracted character
print("Occurrence: "+str((word.count(char))-1))
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}