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3 years ago

Evaluate the function f(p) = p2 + 3p + 1 for p = -2

Mathematics

2 answers:

Gelneren [198K]3 years ago

8 0

P2 + 3p + 1
(-2)2 + 3(-2) +1
-4 +(-6) +1
-9

Vikki [24]3 years ago

7 0

Answer: -1

Step-by-step explanation:

The given function : $f(p) = p^2 + 3p + 1$

To find : The value of the given function ( $f(p) = p^2 + 3p + 1$ ) at p =-2.

We substitute the value of p=-2 in the given function, we get

$f(-2) = (-2)^2 + 3(-2) + 1\\\\\Rightarrow\ f(-2)=4-6+1\\\\\Rightarrow\ f(-2)=-2+1\\\\\Rightarrow\ f(-2)=-1$

Therefore , the value of the given function at p=-2 = -1

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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