Question

Evaluate the function f(p) = p2 + 3p + 1 for p = -2

Answer 1

P2 + 3p + 1
(-2)2 + 3(-2) +1
-4 +(-6) +1
-9

Answer 2

Answer:  -1

Step-by-step explanation:

The given function : $f(p) = p^2 + 3p + 1$

To find :  The value of the given function ( $f(p) = p^2 + 3p + 1$) at p =-2.

We substitute the value of p=-2  in the given function, we get

$f(-2) = (-2)^2 + 3(-2) + 1\\\\\Rightarrow\ f(-2)=4-6+1\\\\\Rightarrow\ f(-2)=-2+1\\\\\Rightarrow\ f(-2)=-1$

Therefore , the value of the given function at p=-2 = -1