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Sergeu [11.5K]
4 years ago
6

Evaluate the function f(p) = p2 + 3p + 1 for p = -2

Mathematics
2 answers:
Gelneren [198K]4 years ago
8 0
P2 + 3p + 1
(-2)2 + 3(-2) +1
-4 +(-6) +1
-9
Vikki [24]4 years ago
7 0

Answer:  -1

Step-by-step explanation:

The given function : f(p) = p^2 + 3p + 1

To find :  The value of the given function ( f(p) = p^2 + 3p + 1) at p =-2.

We substitute the value of p=-2  in the given function, we get

f(-2) = (-2)^2 + 3(-2) + 1\\\\\Rightarrow\ f(-2)=4-6+1\\\\\Rightarrow\ f(-2)=-2+1\\\\\Rightarrow\ f(-2)=-1

Therefore , the value of the given function at p=-2 = -1

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