What is the interval of increase and decrease of f(x)= (x-4)^2 -1
1 answer:
Answer:
(−∞,4)
Step-by-step explanation:
Explanation:
To determine the interval that f(x) is increasing.
increasing when f'(x)>0f'(x)=−2(x−4)← using chain rule
solve −2(x−4)>0
⇒−2x+8>0
⇒x<4
interval is (−∞,4)
graph{-(x-4)^2-3 [-8.89, 8.89, -4.445, 4.44]}
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Answer:
...80u9
Step-by-step explanation:
The answer should be the last one D
Use I = prt
1200 = 8000r(1)
1200/8000 = r
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15% = r
The work shown in the box is correct.