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aivan3 [116]
4 years ago
9

HELP IVE BEEN WAITING A WEEK FOR HELP PLZ LOOK AND HELP NO STUPID WASTEFUL ANSWERS PLZ

Mathematics
1 answer:
bezimeni [28]4 years ago
6 0
Use the distance formula to find the length of  one of the longer lines and do the same for one of the shorter ones.

Longer line using the points (-5,5) and (0,-5):-
length = sqrt ( 5-- 5)^2 + ( -5-0)^2  =  sqrt 125

short line:-  using the points (-5,5) and (-1,7)
length = sqrt (-5--1)^2 + (5-7)^2 )  =  sqrt 29

So the area of the rectangle = sqrt125 * sqrt29 =  60.21  to nearest hundredth
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Sphinxa [80]
96 is the answer i beilive
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Combine like radicals to get your answer. <br><br> image attached
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You spin the spinner once.<br><br> What is P(not 7)?
Flura [38]

Answer:

12.5%

Step-by-step explanation:

The spinner has 8 equal sections, numbered 1, 2, 3, 4, 5, 6, 7, and 8. The only number greater than 7 is 8. There is 1 number greater than 7.

P(greater than 7)  =  

1

8

Write your answer as a decimal. Then convert your answer to a percentage.

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5 0
3 years ago
A suspension bridge with weight uniformly distributed along its length has twin towers that extend 85 meters above the road surf
Dmitry_Shevchenko [17]

Answer:

The required height of the cable is 21.25 meter

Step-by-step explanation:

Consider the provided information.

A suspension bridge with weight uniformly distributed along its length has twin towers that extend 85 meters above the road surface and are 800 meters apart.

Let the road surface is the x-axis, and the point (0,0) represents the point that is on the road surface midway between the two towers.

Now it will form an upward parabola whose vertex is at (0,0), one on either side of vertex at a distance x= 400 or x= -400, and y for each of these points is 85.

The equation of parabola is: y=ax^2

Substitute (400,85) in above formula

85=a(400)^2

\frac{85}{160000}=a

Therefore, the required equation is y=\frac{85}{160000}x^2

We need to Find the height of the cables at a point 200 meters from the center.

So substitute x=200 in above equation.

y=\frac{85}{160000}(200)^2

y=\frac{85}{160000}(40000)

y=\frac{85}{4}

y=21.25

Hence, the required height of the cable is 21.25 meter

5 0
3 years ago
What is the value of the expression:20×5+[27+4)-(36-9)] to the power of 2
kramer

The answer is 498530

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3 years ago
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