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Ahat [919]
3 years ago
13

Write this expression as an equivalent expression without negative exponents:

="TexFormula1" title="3^{-2}" alt="3^{-2}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Arada [10]3 years ago
6 0
The answer is 0.1 and it repeats the 1’s
pentagon [3]3 years ago
4 0
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7 + (10 − 4)2 ÷ 4 × 1\8
natta225 [31]
I’m pretty sure the answer is 12

6 0
3 years ago
Mrs. Escalante was riding a bicycle on a bike path. After riding 2/3 of a mile, she discovered that she still needed to travel 3
VLD [36.1K]
1/5/12 because,
3x4=12,4x2=8 witch would be 8/12 the 3x3=9+the 12=9/12. 9/12+8/12=1/5/12 so the path is 1/5/12.
7 0
4 years ago
Read 2 more answers
Distance between (0,2) and (0,4)
Lorico [155]
There are many ways to do this, I prefer the distance formula it looks like this:
\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
We are given 2 pairs of coordinates: (0,2) and (0,4) 
0=x1
2=y1
0=x2
4=y2
We take the numbers and sub in the values above in place of the variables:
  \sqrt{(0-0)^2+(4-2)^2}
Simplfy it: 
\sqrt{(0)^2+(2)^2}
0^2=0
2^2=4
We are left with :
\sqrt{4}
\sqrt{4} =2
Final answer: 2 
5 0
3 years ago
Read 2 more answers
"-8 is 12 less than a number."
stiks02 [169]

Answer:

The answer would be x<4

7 0
4 years ago
Two angles are given.
LUCKY_DIMON [66]

Answer:

Angle g and h are complementary angles.

Angle g and h are acute angles.

Step-by-step explanation:

The given angles are

m\angle g=(2x-90)^{\circ}

m\angle h=(180-2x)^{\circ}

If sum of two angles is 180, then they called supplementary angles.

If sum of two angles is 90, then they called complimentary angles.

Add both angles.

m\angle g+m\angle h=(2x-90)^{\circ}+(180-2x)^{\circ}

m\angle g+m\angle h=(2x-90+180-2x)^{\circ}

m\angle g+m\angle h=90^{\circ}

The sum of two angles is 90 degree, therefore angle g and h are complementary angles.

Both angles are greater than zero and their sum is 90, it means

0 and 0

Therefore, angle g and h are acute angles.

7 0
3 years ago
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