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2 years ago

Balance the following equation in acidic conditions. Phases are optional. Cu NO3,

1 answer:

5 0

If your equation is <span>Cu+NO^- 3-->Cu^2+NO, then the answer is
</span><span>2 Cu + 1 NO3{-} → 1 Cu^{2+} + 3 NO
</span>
To check if it is balance, this is the solution:
2- Cu- 2
3- N -3
3- O -3

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A sample of nitrogen is initially at a pressure of 1.7 kPa, a temperature of -10 C and a volume of 7.5 m3. Then the volume is de

zhannawk [14.2K]

Answer:

$\boxed{\text{2.6 kPa}}$

Explanation:

To solve this problem, we can use the Combined Gas Laws:

$\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}$

Data:

p₁ = 1.7 kPa; V₁ = 7.5 m³; T₁ = -10 °C

p₂ = ?; V₂ = 3.8 m³; T₂ = 200 K

Calculations:

(a) Convert temperature to kelvins

T₁ = (-10 + 273.15) K = 263.15 K

(b) Calculate the pressure

$\begin{array}{rcl}\dfrac{1.7 \times 7.5 }{263.15} & = & \dfrac{p_{2} \times 3.8}{200}\\\\0.0485 & = & 0.0190p_{2}\\p_{2} & = & \textbf{2.6 kPa}\\\end{array}\\\text{The new pressure of the gas is \boxed{\textbf{2.6 kPa}}}$

7 0

2 years ago

How many protons are found in an atom of platinum (pt)?

Natasha_Volkova [10]

78 protons are found in platinum(pt).

5 0

2 years ago

train travel from hong kong to beijing it traveled at an average speed of 160 km/m in the first 4 hours. after that it traveled

Nonamiya [84]

Answer:

7 hours

Explanation: step 1. 160x4=640

step 2. 1180-640=540

step 3. 540÷180=3

step 4. 3+4=7

5 0

3 years ago

Read 2 more answers

Match each scientist to their discovery regarding the atom

neonofarm [45]

Answer:

Thomson--atoms cotain electron

Ernest Rutherford--atoms have a positive nucleus

R.A Millikan--electrons have Q=-1

Dalton--atoms are indivisible

3 0

2 years ago

Read 2 more answers

In the molecule ClF3, chlorine makes three covalent bonds. Therefore, three of its seven valence electrons need to be unpaired.

Kisachek [45]

Answer:

Explanation:

Chlorine has electronic configuration of 2 , 8 , 7

In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration becomes as follows

$3s^23p_x^23p_y^23p_z^1$ = 7

$3s^23p_x^23p_y^13p_z^13d_{xy}^1$

These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )

3 0

3 years ago