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amid [387]
3 years ago
9

Please help me!!!!!!​

Chemistry
1 answer:
Leona [35]3 years ago
5 0

The answer is B

To write the equilibrium constant for an equation, all you have to do is divide the products by the reactants. The reactants are always on the left side, and the products are always on the right side. The coefficients of the elements will be written as the exponent of that same element. However, in this equation, we do not have to write any exponents, as there are no coefficient but 1.

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What is meant by the term compound? Provide an example
PIT_PIT [208]

Answer:

I hope it helps

Explanation:

  • <em>When two or more elements chemically combine in a fixed ratio by mass, the obtained product is known as a compound. Compounds can be defined as substances consisting of 2 or more different types of elements in a fixed ratio of its atoms. When the elements combine, some individual property of the elements is lost and the newly formed compound has new properties.Chemical Formula: Compounds are represented by their chemical formula. A chemical formula is a symbolic representation of the proportions of atoms that constitute a particular chemical compound.The chemical formula of water is H2O which shows two atoms of hydrogen and one atom of oxygen have combined to form one molecule of H2O. The chemical formula for common salt is NaCl which shows one atom of sodium and one atom of chlorine combine to form one molecule of NaCl.</em>
6 0
3 years ago
25.0 mL of an HBr solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. What is the mo
krok68 [10]

HBr reacts with LiOH and forms LiBr and H₂O as the products. The balanced reaction is

LiOH(aq) + HBr(aq) → LiBr(aq) + H₂O(l)

Molarity (M) = moles of solute (mol) / volume of the solution (L)

Molarity of LiOH = 0.205 M

Volume of LiOH = 29.15 mL = 29.15 x 10⁻³ L

Hence,

moles of LiOH = molarity x volume of the solution

= 0.205 M x 29.15 x 10⁻³ L

= 5.97575 x 10⁻³ mol

The stoichiometric ratio between LiOH and HBr is 1 : 1.

Hence,

moles of HBr in 25.0 mL = moles of LiOH added

= 5.97575 x 10⁻³ mol

Hence, molarity of HBr = 5.97575 x 10⁻³ mol / 25.00 x 10⁻³ L

= 0.23903 M

≈ 0.239 M

Hence, the molarity of the HBr is 0.239 M.

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4 years ago
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