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3 years ago

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Mathematics

2 answers:

eimsori [14]3 years ago

6 0

Area of trapizoid:-

$\blue{A=\dfrac{1}{2}(b_1 +b_2)×h }$

According to the question, 

$\bold{\dfrac{1}{2}×(4+15)×4 }$

$\bold{\dfrac{1}{2}×(19)×4 }$

$\bold{\dfrac{1}{\cancel{2}}×(19)×\cancel{4}}$

$\bold{19×2 ~m^2 }$

$\bold{ 38~m^2 }$

Sunny_sXe [5.5K]3 years ago

4 0

Answer:

38 m²

Step-by-step explanation:

Area of the trapezoid:

A = 1/2(b1 + b2)h
A = 1/2(4 + 15)*4 = 38 m²

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Graph the inequality x > 3.

SpyIntel [72]

You did it wrong it. It should be facing right with an open circle

4 0

3 years ago

Leslie has a voucher worth $5 coupon from Wal-Mart.She visits the store and purchases a wallet that amounted to double the price

jasenka [17]

Answer:

The Cost of wallet was $26.30.

Step-by-step explanation:

Given:

Total billed after redeeming voucher = $34.45

Voucher worth = $5

We need to find the cost of Wallet.

Solution:

Let the amount paid for groceries be 'x'.

Now Given:

She purchases a wallet that amounted to double the price she paid for the groceries she bought.

Cost of wallet = $2x$

Now to find the cost of wallet we will consider the amount before redeeming the voucher.

Hence Total bill before redeeming the voucher = $\$34.45+\$5=\$39.45$

Now We can say that;

Total bill is equal to sum of Cost of wallet and Cost of groceries.

framing in equation form we get;

$x+2x=39.45\\\\3x=39.45$

Dividing both side by 3 we get;

$\frac{3x}{3}=\frac{39.45}{3}\\\\x=\$13.15$

Cost paid for groceries = $13.15

Cost paid for wallet = $2x=2\times 13.15 =\$26.30$

Hence the Cost of wallet was $26.30.

6 0

3 years ago

A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the

creativ13 [48]

Answer:

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

$2r+s=18$

$s=r \theta$

$2r+r \theta=18$

solve for r

$r=\frac{18}{2+\theta}$

step 2

Find the value of s

$s=r \theta$

substitute the value of r

$s=\frac{18}{2+\theta}\theta$

step 3

we know that

The area of complete circle is equal to

$A=\pi r^{2}$

The complete circle subtends a central angle of 2π radians

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

$\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}$

substitute the value of r

$A=\frac{(\frac{18}{2+\theta})^2\theta}{2}$

$A=\frac{162 \theta}{(\theta+2)^2}$

Convert to function notation

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

6 0

4 years ago

Which statement best describes the solution to the equation below ?

SIZIF [17.4K]

Im going to say option 1

8 0

3 years ago

box with a square base and open top must have a volume of 4,000 cm3. Find the dimensions of the box (in cm) that minimize the am

Naya [18.7K]

Answer:

Hence the width, length is 20 cm and height is 10 cm

Step-by-step explanation:

Since the box has a square base, let length = width = x. Also, let the height = y, therefore:

The volume of box = width * length * height

4000 = x * x * y

4000 = x²y

y=4000/x²

The surface area (SA) = area of the base + sum of the area of each side

SA = x² + xy + xy + xy + xy

SA = x² + 4xy

substitute y = 4000/x²

SA = x² + 4x(4000/x²)

SA = x² + 16000/x

Taking the derivative:

SA' = 2x - 16000/x²

making SA' = 0:

0 = 2x - 16000/x²

2x = 16000/x²

2x³ = 16000

x³ = 8000

x = 20 cm

y = 4000 / x² = 4000 / 20² = 10 cm

Hence the width, length is 20 cm and height is 10 cm

6 0

3 years ago

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