Answer: A volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Explanation:
Given:
= 0.300 M,
= ?
= 0.0450 M,
= 250.0 mL
Formula used is as follows.
![M_{1}V_{1} = M_{2}V_{2}](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D)
Substitute the values into above formula as follows.
![M_{1}V_{1} = M_{2}V_{2} \\0.300 M \times V_{1} = 0.0450 M \times 250.0 mL\\V_{1} = 37.5 mL](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D%20%5C%5C0.300%20M%20%5Ctimes%20V_%7B1%7D%20%3D%200.0450%20M%20%5Ctimes%20250.0%20mL%5C%5CV_%7B1%7D%20%3D%2037.5%20mL)
Thus, we can conclude that a volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Cells can be classified as eukaryotic or prokaryotic. Eukaryotic cells contain membrane-bound organelles, including a nucleus, while prokaryotes do not.
Answer:
Bromine is a dark reddish-brown fuming liquid with a pungent odor. Denser than water and soluble in water. Hence sinks in water.
Answer:
The correct answer is b) 2
Explanation:
When is dissolved in water, silver acetate (AgCH₃COO) is dissociated into ions according to the following equilibrium:
AgCH₃COO ⇄ Ag⁺ + CH₃COO⁻
Where Ag⁺ is a silver cation and CH₃COO⁻ is the acetate anion (an organic anion). As we can see, from one single formula unit are obtained 2 ions (1 cation and 1 anion).
Therefore, the correct option is b) - 2