Answer:
This question is incomplete. The completed question is below
Procedure
1. Read and complete a lab safety form.
2. Place about 50 copper pellets into a plastic petri dish. Place the cover on the dish, and secure it with tape.
3. Hold the dish by the edges. Gently vibrate the dish from side to side no more than 1–2 mm. Observe the pellets. Record your observations in your Science Journal.
4. Repeat step 3, vibrating the dish less than 1 cm from side to side.
5. Repeat step 3, vibrating the dish 3–4 cm from side to side.
if the pellets represent particles in matter, what do you think the shaking represents?
Explanation:
This procedure seeks to illustrate the "properties" of particles in matter. The shaking of the pellets represents the movement of the particles of matter (which occurs in liquids and gases). This is because the movement of particles in a liquid and gaseous state freely moves around (reason the petri-dish was vibrated so the pellet particles which serve as the liquid/gaseous particles can move freely).
NOTE: The particles in a solid have a highly restricted movement (or no movement) because of the compact nature of the particles within the solid.
Answer:
Ionic bonding is the attraction between positively- and negatively-charged ions. These oppositely charged ions attract each other to form ionic networks (or lattices). Electrostatics explains why this happens: opposite charges attract and like charges repel.
Explanation:
Someone added the answer already hope that helps you out
Answer: 
.
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
(1)
![S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ](https://tex.z-dn.net/?f=S_%7Bmonoclinic%7D%2BO_2%28g%29%5Crightarrow%20SO_2%28g%29%2Ftex%5D%20%5Btex%5D%5CDelta%20H%5E0_2%3D-296.36kJ)
(2)
The final reaction is:
(3)
By subtracting (1) and (2)
Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ
I believe the answer is 18.
