2304π is the answer and if you don’t want pi it’s 7238.2294738709 feet
Answer:
16
Step-by-step explanation:
Given
C=2r and r=8
So
C=2×8 (as r=8)
C=16 (ans)
U = (-2,3)
V = (3,0)
midpoint of UV
= ( (3-2)/2 , (3+0)/2 )
= ( 1/2 , 3/2)
= ( 0.5 , 1.5)
X = (0.5 , 1.5) [from fig]
midpoint of UV = X
W= (-2,-3)
V =( 3.0)
Y = ( (-2+3)/2 , (-3+0)/2 )
= (0.5 , - 1.5)
Y = ( 0.5 , -1.5) [ from fig ]
Y is the midpoint of WV
by midpoint theorem ,
UW = 2( XY )
Answer:
1813.137 KJ
Step-by-step explanation:
potential energy of the body = mgH
where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m
here m= 1000 kg, g= 9.81 m/s^2 and H= 607 feet = 607×0.305= 185.135 m
hence the potential energy p= 1000×9.81×185.135= 1813137.2 J
= 1813.137 KJ
hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
Answer:
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