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34kurt
3 years ago
15

Please help! What is the volume of the triangular pyramid?

Mathematics
2 answers:
drek231 [11]3 years ago
6 0

Answer:

10 m³

Step-by-step explanation:

My apologies for attaching the explanation in a pic, brainly wouldn't let me upload my text answer for some reason.

vivado [14]3 years ago
5 0

Answer:

30cm3

Step-by-step explanation:

Volume=Base area *height

Base area is a triangle=1/2 *base*height

1/2*3*4=6cm2

Height=5cm

Volume=6*5=30cm3

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1/4
7 0
3 years ago
Which graph represents the following piecewise defined function?
kenny6666 [7]
The correct answer is shown in attached figure
To find the correct graph, we should study the continuity of the function

Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2

Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3


From the previous results the correct graph is the last as shown in attached graph.



5 0
3 years ago
Read 2 more answers
Let x and y be independent each uniformly distributed on {1,2,...,n} find p(x < y )
bulgar [2K]
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have   (legend:  < : x<y   = : x=y   > : x>y

y      1  2  3  4
x
1      = <  <  <
2      > =  <  < 
3      >  >  = <
4      >  >  >  =

We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore, 
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)

However, if the sample space is continuous, it will be simply p(x<y)=1/2.

8 0
3 years ago
Factor 6y^2(y^2+6y+9) completely.
natali 33 [55]

6y^2(y^2+6y+9)\\\\=6y^2(y^2+2\cdot 3 \cdot y   + 3^2)\\\\=6y^2(y+3)^2\\\\=6y^2(y+3)(y+3)

7 0
2 years ago
Choose the correct word that completes each statement about inscribing a square in a circle.
Anna11 [10]

Answer:

1. Perpendicular

2. Isosceles

3. Never

Step-by-step explanation:

1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.

2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )

In Δ COB , By using pythagoras : BC² = OC² + OB²  ..........( 2 )

But, OA = OC because both are radius of same circle

So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC

⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.

3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius


7 0
3 years ago
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