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Answer:
Option A is the right answer.
Explanation:
In any programming language, when a user needs to define the constant variable then he should need to define the variable in capital letter. It is not necessary for the compiler point of view but it is necessary for the standardization point of view. It means that when a user does not define the constant variable in the capital letter then it will never give an error.
Option "a" also states that the variable is constant and the scenario is to define the variable in capital letter hence option a is correct while the other is not because--
- Option b states that the user-defined reference variable but the reference variable is defined with the help of (*) symbol.
- Option c states about the loop variable but the loop variable also can define by small letters.
- Option d states that it is used for dynamic value but for dynamic variable a user can define small letters.
Given that,
Mass of the block, m = 2700 g
Let the dimensions of the block are 20 cm, 5 cm and 10 cm.
To find,
The density of the granite.
Solution,
Let d is the density of the granite. We know that the density of an object is equal to the mass per unit volume. So,
d = m/V
or
So, the density of the block is 2.7 m/s².
A compiler converts code written by humans in to machine code, in which computers are able to understand and execute.
Well, you didn't say what language, so here's in Java:
public static void PrintShampooInstructions(int numCycles)
{
if(numCycles < 1)
System.out.println("Too few.");
else if (numCycles > 4)
System.out.println("Too many.");
else
{
for(int i = 1; i <= numCycles; i++)
{
System.out.println(i+": Lather and rinse.");
}
System.out.println("Done.");
}
}
And also in an image, in case you can't really see it
