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ivanzaharov [21]
3 years ago
13

Freckles are small, spots of a skin pigment called melanin. Most fair-skinned, red-haired people have them. Freckles are control

led primarily by the MC1R gene. Freckles are a dominant trait: parents who have freckles tend to have children with freckles. Bill and Barb both have freckles. Yet of their four children, one child does not have freckles! What must be the genotypes of Bill and Barb?
A) BB and BB
B) BB and Bb
C) Bb and Bb
D) Bb and bb

Biology
2 answers:
Yakvenalex [24]3 years ago
7 0

Answer:

The correct answer would be C) Bb and Bb.

The phenotype of both parents is a dominant trait. Thus, both of them must contain at least one copy of the dominant allele.

Therefore, the genotype of both parents would be B_.

Case I: When both parents are homozygous dominant, that is, BB. All the offspring would be BB, that is, all have freckles.

Case II: When one parent is homozygous dominant and other is heterozygous, that is. BB and Bb. All the offspring would be either BB or Bb. Thus, all the offspring would have freckles.

Case III: When both the parents are heterozygous dominant, that is, both are Bb. The offspring can have BB, Bb, or bb. One out of four children would have no freckles.

Thus, the correct answer would be C) Bb and Bb.

lbvjy [14]3 years ago
6 0

its d Bb and bb i think sorry if its wrong

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The formula for calculating the estimated number of individuals in the population is given as:

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This possibility can be reduced if the student used tags that does not slip off easily.

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