The answer is B. guidelines for safe laboratory practices
Biodiversity rises with altitude initially before falling with height beyond that. Up until it reaches a diversity peak at about 1 300 to 1 800 m.
- The biodiversity increases at higher geographical locations because There are more hiding locations. They are better for crop growth. They frequently include more than one kind of habitat.
- As latitude or altitude change, so does biodiversity. As we descend from high to low elevations, the diversity increases (i.e., from poles to equator).
- While the environment is harsh and plants have a brief growing season in the temperate region, tropical rain forests provide year-round growth-friendly circumstances.
- This enables the emergence and expansion of several species. On a mountain, there is an initial increase in species diversity after which there is a decline in species variety as you go up in elevation.
- At higher elevations, temperature drops and seasonal variations increase, which significantly diminishes.
learn more about biodiversity here: brainly.com/question/26110061
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<span>Most children acquire a firm sense of gender identity by the age of three</span>
Answer:
The person has been dead for approximately 15,300 years
Explanation:
<u>Available data</u>:
- The half-life of carbon 14 is 5,600 years
- The human skeleton level of carbon 14 is 15% that of a living human
To answer this question we can make use of the following equation
Ln (C14T₁/C14 T₀) = - λ T₁
Where,
- C14 T₀ ⇒ Amount of carbon in a living body at time 0 = 100%
- C14T₁ ⇒ Amount of carbon in the dead body at time 1 = 15%
- λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
- T₀,₅ ⇒ The half-life of carbon 14 = 5600 years
- T₀ = 0
- T₁ = ???
Let us first calculate the radioactive decay constant.
λ = (Ln2)/T₀,₅
λ = 0.693/5600
λ = 0.000123
Now, let us calculate the first term in the equation
Ln (C14T₁/C14 T₀) = Ln (15%/100%) = Ln 0.15 = - 1.89
Finally, let us replace the terms, clear the equation, and calculate the value of T₁.
Ln (C14T₁/C14 T₀) = - λ T₁
- 1.89 = - 0.000123 x T₁
T₁ = - 1.89 / - 0.000123
T₁ = 15,365 years
The person has been dead for approximately 15,300 years
