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notsponge [240]
3 years ago
15

❗❗❗❗❗❗❗HELP❗❗❗❗❗❗❗

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0

D,the quadratic function turning point is (-2,-1) while the other graphs change direction at (-2,3)

Step-by-step explanation:

The point where the graph of a quadratic function changes direction is called a turning point.This is the point where the curve changes to face up or down according to the function.The functions in A,B and C have a common turning point (-2,3) that also appears in the table.The function in D has a turning point at (-2,-1) that is different from the other three functions.

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I'm supposed to simplify this.
tekilochka [14]

Answer:

C

Step-by-step explanation:

the proof of the answer is seen in the diagram

4 0
3 years ago
A line passes through (-2,5) and has slope. What is an equation of the line in point-slope form?
shepuryov [24]

Answer:

Step-by-step explanation:

since the question does not have a given slope you can just put the point into the point slope formula   y-y1 = m(x-x1)  

y-5 = m(x-(-2))

y-5 = m(x+2)

since the slope is not given, leave it like that

4 0
2 years ago
How can the decimal 0.57 be written as a fraction
Akimi4 [234]
If you want to convert 0.57 into a fraction, you can do it like this:
<span>
<span>0.57 equals to 57/100 </span></span><span>(you can't do anything else because 57 and 100 don't have common factors).

</span><span><span /><span>The result is 57/100.</span>
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7 0
3 years ago
Read 2 more answers
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
Sum of exterior angles in a polygon?
soldi70 [24.7K]

Answer:

360

Step-by-step explanation:

The exterior angles always add up to 360 in a polygon because it's the sum of all the vertexes which would make a circle.

8 0
3 years ago
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