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uysha [10]
4 years ago
8

A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC b

elow is equal to the measure of the exterior angle.
Step 1: m∠x + m∠y + m∠z = 90 degrees (sum of adjacent angles)
Step 2: m∠w + m∠z = 180 degrees (supplementary angles)
Step 3: Therefore, m∠x + m∠y + m∠z = m∠w + m∠z
Step 4: So, m∠x + m∠y = m∠w

In which step did the student first make a mistake and how can it be corrected?

Step 1; it should be m∠x + m∠y + m∠z = 180 degrees (sum of angles of a triangle)
Step 1; it should be m∠x + m∠y + m∠z = 180 degrees (corresponding angles)
Step 2; it should be m∠w + m∠z = 90 degrees (supplementary angles)
Step 2; it should be m∠w + m∠z = 90 degrees (adjacent angles)

Mathematics
2 answers:
lana [24]4 years ago
6 0

Answer:

The correct option is 1.

Step-by-step explanation:

The according to the angle sum property of triangle, the sum of interior angles of a triangle is 180°.

Step 1: According to the student in triangle ABC,

\angle x+\angle y+\angle z=90^{\circ}

Which is not correct because the sum of interior angles of a triangle is 180°. So, he did a mistake in step 1.

In triangle ABC,

\angle x+\angle y+\angle z=180^{\circ}    ... (1)       (sum of angles of a triangle)

Step 2: \angle w+\angle z=180^{\circ}     .... (2)    (supplementary angles)

Step 3: Equating (1) and (2), we get

\angle x+\angle y+\angle z=\angle w+\angle z

Stpe 4: \angle x+\angle y=\angle w

Therefore the correct option is 1.

blsea [12.9K]4 years ago
5 0
The correct answer is A.  All triangles' interior angles equal 180.
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3 years ago
A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether
salantis [7]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- A survey was conducted among the College students for their motivations of using credit cards two years ago. A randomly selected group of sample size n = 425 college students were selected.

- The results of the survey test taken 2 years ago and recent study are as follows:

                                           

                                           Old Survey ( % )            New survey ( Frequency )

                  Reward                 27                                              112

                  Low rate               23                                              96

                  Cash back           21                                              109

                  Discount              9                                               48

                  Others                  20                                             60

- We are to test the claim for any changes in the expected distribution.

We will state the hypothesis accordingly:

Null hypothesis: The expected distribution obtained 2 years ago for the motivation behind the use of credit cards are as follows: Rewards = 27% , Low rate = 23%, Cash back = 21%, Discount = 9%, Others = 20%

Alternate Hypothesis: Any changes observed in the expected distribution of proportion of reasons for the use of credit cards by college students.

( We are to test this claim - Ha )

We apply the chi-square test for independence.

- A chi-square test for independence compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each other.

- We will compute the chi-square test statistics ( X^2 ) according to the following formula:

 

                                X^2 = Sum [ \frac{(O_i - E_i)^2}{Ei} ]

Where,

 O_i : The observed value for ith data point

 E_i : The expected value for ith data point.

- We have 5 data points.

So, Oi :Rewards = 27% , Low rate = 23%, Cash back = 21%, Discount = 9%, Others = 20% from a group of n = 425.

     Ei : Rewards = 112 , Low rate = 96, Cash back = 109, Discount = 48, Others = 60.

Therefore,

                               

                     X^2 = [ \frac{(112 - 425*0.27)^2}{425*0.27} +  \frac{(96 - 425*0.23)^2}{425*0.23} +  \frac{(109 - 425*0.21)^2}{425*0.21} +  \frac{(48 - 425*0.09)^2}{425*0.09} +  \frac{(60 - 425*0.20)^2}{425*0.20}]\\\\X^2 = [ 0.06590 + 0.03132 + 4.37044 +  2.48529 +  7.35294]\\\\X^2 = 14.30589

- Then we determine the chi-square critical value ( X^2- critical ). The two parameters for evaluating the X^2- critical are:

                     Significance Level ( α ) = 0.10

                     Degree of freedom ( v ) = Data points - 1 = 5 - 1 = 4  

Therefore,

                     X^2-critical = X^2_α,v = X^2_0.1,4

                    X^2-critical = 7.779

- We see that X^2 test value = 14.30589 is greater than the X^2-critical value = 7.779. The test statistics value lies in the rejection region. Hence, the Null hypothesis is rejected.

Conclusion:-

This provides us enough evidence to conclude that there as been a change in the claimed/expected distribution of the motivations of college students to use credit cards.

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