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Pavel [41]
3 years ago
14

x -1" alt="f(x)= 3x+1 , g(x)- 2x -1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)

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Q # 4 anybody help me please
Marysya12 [62]

<u>Answer</u>

-5/3, -1,  0.7,  √2,   √5


<u>Explanation</u>

√5 = 2.236

-1 ⇒ this is less than 1.  

-5/3 = -1.666667    this is less than 1.  -5/3 < -1

0.7 > -1

√2 = 1.414        ⇒     √5 > √2

Arranging them from the least to the greatest;

-5/3, -1,  0.7,  √2,   √5

8 0
3 years ago
Which is greatest 895mm or 8,98mm?
inessss [21]
898 mm because 8.98 is a lot smaller, it's only in the ones place.
6 0
3 years ago
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Suppose I have Rs 1000 and I put it in the bank. What will be the amount I have after 5 years if Interest is 5% per annum?​
vichka [17]

Answer:

Its 250 the answer which i got.

8 0
2 years ago
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Can someone please help me with this one? Tysm! ^^
lana [24]
2/3 x 3/4 =6/12=1/2
(Multiply numerators, multiply denominators, simplify)
4 0
3 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
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