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lions [1.4K]
3 years ago
6

Write an equation for the line parallel to the given line that contains C. C(2,8); y = - 4x + 3

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer: i love brinly its the best

the value of x is 4, make m||n

Step-by-step explanation:

sorry if this is wrong

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X+5/-2=x-10/7<br><br> What does x=
topjm [15]
X= 1 x+5/2=1 which is x .10/2
6 0
3 years ago
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Simplify.<br> 10u -4u<br> Please help
vovikov84 [41]

Answer:

6u

Step-by-step explanation:

The two terms 10u and 4u are like terms because they both carry the same variable (u) with the same degree (1). So, we can just subtract them as if they were normal numbers 10 - 4:

10u - 4u = 6u

Thus, the answer is 6u.

Hope this helps!

8 0
3 years ago
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What is the value of x in the equation 5x+3=4x?
Volgvan

Answer:

x = -3

Step-by-step explanation:

5x + 3 = 4x,

x + 3 = 0,

x = -3

3 0
3 years ago
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assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
4,2,1,...<br> Find the 9th term.
harkovskaia [24]

Answer: 0.015625

Step-by-step explanation:

i noticed the pattern. it is getting divided by 2 each time. so, i just divided each new number by 2 and got 0.015625.

8 0
3 years ago
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