All categories

3 years ago

What is the factored form of 2x2 − 7x − 15? (2x + 3)(x − 5) (2x + 5)(x − 3) (2x − 7)(x + 8) (2x + 8)(x − 7)

Mathematics

2 answers:

lesantik [10]3 years ago

6 0

2x^2 - 7x - 15 =
(2x + 3)(x - 5) <==

Vadim26 [7]3 years ago

5 0

2x^2-7x-15
is a factor of (2x+3)(x-5)

You might be interested in

What are the factors of 68

elixir [45]

$68=2\times34\\\\68=4\times17$

4 0

3 years ago

Read 2 more answers

Three times the sum of a number and two is equal to -9.

Svetllana [295]

Answer:

Step-by-step explanation:

use a equation calculator it really helps

8 0

3 years ago

- ignore this :) thank you v much.

yan [13]

Answer:

i dont know what you mean by ignore this and it looks like you got it

Step-by-step explanation:

8 0

2 years ago

Diagram shows two perpendicular straight lines,OB and CBD,drawn on a Cartesian plane.

Tems11 [23]

Answer: (a) y = -3x + 10

$\bold{(b)\x=\bigg(\dfrac{10}{3},0\bigg)}$

Step-by-step explanation:

The slope of line CD is perpendicular to line OB, which means they have opposite and reciprocal slopes.

Step 1: Find the slope of OB using the formula: $m=\dfrac{y_2-y_1}{x_2-x_1}$

(x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 1)

$m=\dfrac{1-0}{3-0} = \dfrac{1}{3}$

Step 2: Find the slope of CD (opposite and reciprocal of OB)

$m = \dfrac{1}{3}\qquad m_\perp=-\bigg(\dfrac{3}{1}\bigg) = -3$

Step 3: Input the perpendicular slope and the slope into the Point-Slope formula: y - y₁ = m(x - x₁)

(x₁, y₁) = (3, 1) because it is the point the line will pass through

y - 1 = -3(x - 3)

y - 1 = -3x + 9 distributed -3 into (x - 3)

y = -3x + 10 added 1 to both sides

***********************************************************************

The x-intercept of DQ is the same x-intercept as CD. The x-intercept is when y = 0

y = -3x + 10

0 = -3x + 10

-10 = -3x subtracted 10 from both sides

$\dfrac{10}{3}=x$ divided both sides by -3

3 0

2 years ago

Explain how to find (f^-1)’(b), given that b=f(a).

Ganezh [65]

Answer:

(f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)

Step-by-step explanation:

The function f⁻¹(x) is the reflection of the function f(x) across the line y=x. Every point (a, b) that is on the graph of f(x) is reflected to be a point (b, a) on the graph of f⁻¹(x).

Any line with slope m reflected across the line y=x will have slope 1/m. (x and y are interchanged, so m=∆y/∆x becomes ∆x/∆y=1/m) Since f'(x) is the slope of the tangent line at (x, f(x)), 1/f'(x) will be the slope of the tangent line at (f(x), x).

Replacing x with f⁻¹(x) in the above relation, you get ...

... (f⁻¹)'(x) = 1/f'(f⁻¹(x)) will be the slope at (x, f⁻¹(x))

Putting your given values in this relation, you get

... (f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)

7 0

3 years ago