Answer:
the trid one becasue
Step-by-step explanation:
To get the correct answer, you can count the total number of shaded tenths and the total number of shaded hundredths and then regroup.
There are 9 shaded tenths and 18 shaded hundredths. Regroup 10 hundredths into 1 tenth to get 10 tenths and 8 hundredths. Then regroup the 10 tenths in one whole, giving you 1 whole and 8 hundredths. The product is 1.08.
Another way to get the answer is to count the total number of shaded hundredths. There are 108 hundredths. Regroup 100 of them as one whole, giving you 1 whole and 8 hundredths.
2$ more than. I’m pretty sure that is the answer if not I’m sorry
so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".
however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus
k = n - 1.
however, if k = n - 1, then
k + 1 = n. So let's use those fellows then,
Answer:
<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)
Step-by-step explanation:
To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:
Extended Rotation Rules
- 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
- 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
- 180°-rotation >> (x, y) → (-x, -y)
So, perform your rotation:
270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]
→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]
→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]
I am joyous to assist you anytime.
Answer:
Step-by-step explanation:
20
×48
-------
160
800
---------
960
Hope this helps
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