(2x^2 + 16x + 30) / (5x^2 + 13x -6)
Start by factoring the numerator and denominator.
Cancel any like factors.
2(x^2 + 8x + 15)
2(x + 5)(x + 3) / (5x -2)(x + 3
2(x + 5) / (5x - 2)
The third choice
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
3000
Step-by-step explanation:
Answer:
The missing side length is 3 units long.
Step-by-step explanation:
Use the Pythagorean Theorem where c²=a²+b²,
c=2√3, c²=12
a²=√3, a²=3
Solving for the missing side yields a side length of 3.
