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krok68 [10]
3 years ago
11

A series circuit and identify how voltage is split up by each load in the circuit?

Computers and Technology
1 answer:
Vlada [557]3 years ago
4 0

The same current flows through each part of a series circuit. The total resistance of a series circuit is equal to the sum of individual resistances. ... The voltage drop across a resistor in a series circuit is directly proportional to the size of the resistor. If the circuit is broken at any point, no current will flow.

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7 0
3 years ago
Read 2 more answers
What command issued from the command prompt will show the route that a packet travels from the issuing computer to another compu
svetoff [14.1K]

Answer:

B)tracert

Explanation:

Tracery Command can be regarded as

network diagnostic tool, it is used in tracking process of pathway of packet ranging from source to destination on IP network. It as well allows to know real time of each hops that are been taken by a packet as it enroutes to it's destination. The traceroute can be run by following these steps:

✓Open the run window

✓Open Command prompt, this can be done by enter "cmd" then enter.

✓ input" tracert" then destination ( Ip address or web address)

It should be noted that Tracery command issued from the command prompt will show the route that a packet travels from the issuing computer to another computer.

6 0
2 years ago
You are asked to simulate a binary search algorithm on an array of random values.An array is the list of similar type of element
Alex Ar [27]

Answer:

Explanation:

Problem statement:

to simulate a binary search algorithm on an array of random values.

Binary Search: Search a sorted array by repeatedly dividing the search interval in half. Begin with an interval covering the whole array. If the value of the search key is less than the item in the middle of the interval, narrow the interval to the lower half. Otherwise narrow it to the upper half. Repeatedly check until the value is found or the interval is empty.

Input/output description

Input:

Size of array: 4

Enter array:10  20 30 40

Enter element to be searched:40

The Output will look like this:

Element is present at index 3

Algorithm and Flowchart:

We basically ignore half of the elements just after one comparison.

Compare x with the middle element.

If x matches with middle element, we return the mid index.

Else If x is greater than the mid element, then x can only lie in right half subarray after the mid element. So we recur for right half.

Else (x is smaller) recur for the left half.

The Flowchart can be seen in the first attached image below:

Program listing:

// C++ program to implement recursive Binary Search

#include <bits/stdc++.h>

using namespace std;

// A recursive binary search function. It returns

// location of x in given array arr[l..r] is present,

// otherwise -1

int binarySearch(int arr[], int l, int r, int x)

{

   if (r >= l) {

       int mid = l + (r - l) / 2;

       // If the element is present at the middle

       // itself

       if (arr[mid] == x)

           return mid;

       // If element is smaller than mid, then

       // it can only be present in left subarray

       if (arr[mid] > x)

           return binarySearch(arr, l, mid - 1, x);

       // Else the element can only be present

       // in right subarray

       return binarySearch(arr, mid + 1, r, x);

   }

   // We reach here when element is not

   // present in array

   return -1;

}

int main(void)

{ int n,x;

cout<<"Size of array:\n";

cin >> n;

int arr[n];

cout<<"Enter array:\n";

for (int i = 0; i < n; ++i)

{ cin >> arr[i]; }

cout<<"Enter element to be searched:\n";

cin>>x;

int result = binarySearch(arr, 0, n - 1, x);

   (result == -1) ? cout << "Element is not present in array"

                  : cout << "Element is present at index " << result;

   return 0;

}

The Sample test run of the program can be seen in the second attached image below.

Time(sec) :

0

Memory(MB) :

3.3752604177856

The Output:

Size of array:4

Enter array:10  20 30 40

Enter element to be searched:40

Element is present at index 3

Conclusions:

Time Complexity:

The time complexity of Binary Search can be written as

T(n) = T(n/2) + c  

The above recurrence can be solved either using Recurrence T ree method or Master method. It falls in case II of Master Method and solution of the recurrence is Theta(Logn).

Auxiliary Space: O(1) in case of iterative implementation. In case of recursive implementation, O(Logn) recursion call stack space.

8 0
2 years ago
Assign a variable solve Equation with a function expression that has three parameters (x, y, and z) and returns the result of ev
tangare [24]

Answer: Following is a python code

def solveEquation(x,y,z):

   res=z-y+(2*x)  #stores expression's value

   return res

solveEquation(2,1,4)  #calls function

OUTPUT :

7

Explanation:

In the above code solveEquation is the function which takes three arguments x,y and z and their type is decided while calling the function and passing the values to these arguments. After the values are passed, an equation is written which is solved and the result is stored in variable res and then that variable's value is returned.

5 0
3 years ago
Output a brief description of the game of hangman and how to play.
musickatia [10]

Answer:

Hangman is game which can be played with a pencil or pen and a paper. It is a multiplayer game which requires minimum two players. It is a guessing game, in which a player thinks of a word or a phrase and other player or players tries to guess it correctly, letter by letter or whole word or phrase at once, in a certain number of guesses.

In this game, the word to be guessed is represented by dashes. If the guessed word or letter is correct, the player fills the blank spaces. But if the guessed word or letter is wrong, the player draws an element of a hanged man stick figure one by one as a tally mark.

This game ends if the player who is guessing guesses the word or the phrase correctly and the guesser wins; or if the player guesses enough wrong letters of phrases that the other player finishes the drawing of the hangman and the guesser loses.

3 0
3 years ago
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