Explanation:
nose pero también se usa para la musica electronica
Answer:
Following are the solution to the given choices:
Explanation:
Given:
double currentBalance[91];//defining a double array
In point a:
The name of the array is= currentBalance.
In point b:
91 double values could be saved in the array. It requires 8bytes to hold a double that if the array size is 91*8 = 728
In point c:
Each element's data type is double.
In point d:
The array index range of values is between 0 and 90 (every array index starts from 0 and ends in N-1, here N=91).
In point e:
To access first element use currentBalance[0], for middle currentBalance[91/2] , for last currentBalance[90]
Answer:
your answer may be(utility software)
Answer:
Following are the code to this question:
list_val = input()#defining a integer variable for input value
test_grades = list(map(int, list_val.split()))#defining test_grades as a list
sum_extra = -999 #defining sum_extra that holds negative integer value
sum_extra = 0#defining sum_extra that holds value
for y in range(len(test_grades)):#defining a for loop to check range of list
if(test_grades[y] > 100):# defining if block that check list value is greater then 100
sum_extra = sum_extra + (test_grades[y] - 100)#use sum_extra variable to hold extra value and add this value
print('Sum extra:', sum_extra)#print value
Output:
101 83 107 90
Sum extra: 8
Explanation:
In the above code a, "list_val" variable is declared, that uses an input method to input the values and declared a "test_grades" variable that uses a list method to add all values in the list.
In the next step, the "sum_extra" variable is declared, which holds some values and defines a for loop to check the range of the "test_grades", and define a if block, that checks list value is greater than 100. If the condition is true, it will remove the extra value, and add it into the sum_extera variable and add its value, and at the last use, print variable to print its value.
