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VMariaS [17]
3 years ago
5

Find the area of the parallelogram. 10 60 4

Mathematics
1 answer:
posledela3 years ago
8 0

Answer:

40

Step-by-step explanation:

area is length times width for 2d shapes. do 4x10 the are is 40

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A rectangular painting has a diagonal measure of 25 inches and an area of 168 square inches. Use the formula for the area of a r
Sphinxa [80]
H^2=x^2+y^2  and xy=168 so y=168/x

625=x^2+28224/x^2

625=(x^4+28224)/x^2

x^4-625x^2+28224=0

I'll use the quadratic because this is a big number :P

x^2=(625±√(277729))/2

x^2=(625±527)/2

x^2=49

x=7

168/7=24

So the dimensions of the painting is 7 inches by 24 inches.
8 0
3 years ago
I need help ASAP!!!!!!1
Archy [21]

Answer:

76 degrees

Step-by-step explanation:

5 0
3 years ago
explain how to write an equation of the line that passes through the point (3,1) and is a parallel to the line y=5 and (b) perpe
Andrews [41]

Answer:

The parallel line would be y = 1 and the perpendicular line would be x = 3.

Step-by-step explanation:

In order to find a line parallel to y = 5, we must first note that y = 5 is a horizontal line. This means to be parallel, the line must also be horizontal. All horizontal lines are written in the form of y = (just a number). Since we can see the value of y in the ordered pair as 1, we know the equation is y = 1.

The exact opposite logic can be used to find the perpendicular line. Since the first line is horizontal, the next one will be vertical, which are written as x = (a number). We again look to the ordered pair to determine the number and write the equation as x = 3

3 0
4 years ago
A varies directly as the square of b and inversely as the cube of
aev [14]

Step-by-step explanation:

the answer is in the picture above

4 0
3 years ago
5. Given: 2q – r = p, r = q – s, p = q + 2r; Prove: s = 2r
almond37 [142]

Answer:

2q -r= p -----(1)

r= q -s -----(2)

p= q +2r -----(3)

From (2):

r +s= q <em>(</em><em>+</em><em>s </em><em>on </em><em>both </em><em>sides)</em>

s= q -r -----(4) <em>(</em><em>-r </em><em>on </em><em>both </em><em>sides)</em>

Substitute. (3) into (1):

2q -r= q +2r

2q -q= 2r +r

q= 3r -----(5)

Substitute (5) into (4):

s= 3r -r

s= 2r (proved)

5 0
3 years ago
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