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sp2606 [1]
3 years ago
15

How do I evaluate x+y=10

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0
Hi there! Evaluate means to solve so we are going to solve x+y=10. Add both sides to -y, x+y+-y=10+-y=X=-y+10. Therefore, the answer is x=-y+10
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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
madam [21]

The true statement is:

"The range of the function is all real numbers less than or equal to 9."

<h3>Which statements are true?</h3>

Here we have the quadratic function:

f(x) = -x^2 - 4x + 5

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

f(x) = -x^2 - 4x + 5

So the vertex is at:

x = 4/(2*-1) = -2\\

Then the y-value of the vertex is:

f(-2) = -(-2)^2 - 4*(-2) + 5 = -4 + 8 + 5 = 9

So the range is the set of all real numbers less than or equal to 9.

So the above statement is false, and the final one:

"The range of the function is all real numbers less than or equal to 9."

Is the true statement.

If you want to learn more about quadratic functions:

brainly.com/question/1214333

#SPJ1

8 0
2 years ago
Helppp me please!!! ​
Artist 52 [7]

Answer:

18 hdhb

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (-3, -2)(−3,−2) and (3, 6)(3,6)? Put your answer in fully reduced
il63 [147K]

Answer:

The equation of the line is y = \frac{4}{3} x + 2

Step-by-step explanation:

The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where

  • m is the slope of the line whose rule is m=\frac{y2-y1}{x2-x1}
  • b is the y-intercept, you can find it by substituting x, y in the equation by (x1, y1) OR (x2, y2)

Let us solve the question:

∵ The line passes through the points (-3, -2) and (3, 6)

∴ x1 = -3 and x2 = 3

∴ y1 = -2 and y2 = 6

→ Use the rule of m to find it

∵ m=\frac{6-(-2)}{3-(-3)}=\frac{6+2}{3+3}=\frac{8}{6}

→ Simplify it by dividing up and down by 2

∴ m = \frac{4}{3}

→ Substitute its value in the form of the equation above

∴ y = \frac{4}{3} x + b

→ To find b substitute x and y by x1 and y1

∴ -2 = \frac{4}{3} (-3) + b

∴ -2 = -4 + b

→ Add 4 to both sides

∴ -2 + 4 = -4 + 4 + b

∴ 2 = b

→ Substitute it in the form of the equation

∴ y = \frac{4}{3} x + 2

∴ The equation of the line is y = \frac{4}{3} x + 2

6 0
3 years ago
-4 (x + 10) -6 = -3 (x-2)
Luba_88 [7]

Answer:

-52

Step-by-step explanation:

3 0
3 years ago
Multiply the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending pow
attashe74 [19]
32x^2+64x+12x+21 => 32x^2+76x+21 you multiply the two equation together and you will get this
4 0
3 years ago
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