It's 130, any quadrilateral's angles add up to 360 and those numbers add up to 230, 360-230 = 130
Answer:
so the first picture is it graphed without solving it and the second graph is the answer to it graphed
Step-by-step explanation:
Answer:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Step-by-step explanation:
We want to evaluate ![[11.5-(2.5*3)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2)
Let us evaluate within the parenthesis first:
![[11.5-(2.5*3)]^2=[11.5-(7.5)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-%287.5%29%5D%5E2)
![\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2](https://tex.z-dn.net/?f=%5Cimplies%20%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-7.5%5D%5E2)
We again subtract within the bracket to obtain:
![[11.5-(2.5*3)]^2=[4]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B4%5D%5E2)
This finally gives us:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Answer:
1.) 2 over 5
2.)7.5 over 50
3.)1 1/2
5.)0.95%
6.)2.5%
7.)0.94
i cant read 9 and ten
11.)61 over 100
12.)7 over 25
13.)207 over 1000
15.)14 over 25
16.)13 over 50
17.)3 over 500
19.)5 over 8
20.)42 over 125
21.)3 over 250
I tried my best!! hope this helps you out