Answer:
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Step-by-step explanation:
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So #1 you're lazy like me. But
1: x=1
2. No solution
3: x= -4/-3
4: 46=13 false
5: 37=-37 false
Angles 1, 3, and 4 make up a straight line.
Thus, 3x + 90 + 3x - 6 = 180 (angle sum of straight line)
6x - 6 = 90
6x = 96
x = 16
Now angle 1 becomes 3(16) = 48
Angle 1, 2, and 3 also make up a straight line.
Thus, angle 2 + 48 + 90 = 180
angle 2 + 138 = 180
angle 2, therefore, becomes 42. In essence, (A)
X-y=-10
x=-10-y
7x+7y=-14
7(-10-y)+7y=-14
-70-7y+7y=-14
0y=56
y=0
x=-10-y
x=-10-0
x=-10
I’m not 100% sure if this is right, so I hope someone checks this over :)
Answer:
Therefore, HL theorem we will prove for Triangles Congruent.
Step-by-step explanation:
Given:
Label the Figure first, Such that
Angle ADB = 90 degrees,
angle ADC = 90 degrees, and
AB ≅ AC
To Prove:
ΔABD ≅ ΔACD by Hypotenuse Leg theorem
Proof:
In Δ ABD and Δ ACD
AB ≅ AC ……….{Hypotenuse are equal Given}
∠ADB ≅ ∠ADC ……….{Each angle measure is 90° given}
AD ≅ AD ……….{Reflexive Property or Common side}
Δ ABD ≅ Δ ACD ….{By Hypotenuse Leg test} ......Proved
Therefore, HL theorem we will prove for Triangles Congruent.