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2 years ago

5

A wedding planner she did the 234 gas at a reception so that each table have the same number of guest if each table could see no

more than 20 people what is the largest possible number of guest at each table

1 answer:

Studentka2010 [4]2 years ago

6 0

Answer:

the largest number of people she can sit at a table is 18.

Step-by-step explanation:

there would be 13 tables

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(5y 3 + 20y 2 – 12)(2y3 - 15y2 + 4y + 16)

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2 years ago

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2 years ago

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zepelin [54]

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3 years ago

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olga2289 [7]

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$\sin(30) = \frac{n}{ \frac{10 \sqrt{3} }{3} } \\ 0.5 = \frac{n}{5.77} \\ n = 2.88 = \frac{5 \sqrt{3} }{3}$

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2 years ago

Which two values of x are roots of the polynomial below?<br> x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

<u>Solution:</u>

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

Hence, the roots of given polynomial are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

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2 years ago