Answer:
B and D
Step-by-step explanation:
This must be a six sided figure
A. 15 x 15. This would be area
B. 6 x 15. This is the sum of six sides of 15
C. 15 + 6. This is the sum of 2 sides of different length
D. 15 + 15 + 15 + 15 + 15 + 15. This is the sum of six sides of length 15
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
It would be 10x10 =100 or in other word 10 times itself. Also known as 10 with the 2 hanging over the 10.
Use FOIL (first, outer, inner, last) :
(<span>5h-3)(3h+7)
</span>(5h)(3h)+7(5h)-3(3h)-3(7)
15h^2+35h-9h-21
D: 15h^2+26h-21
Hope this helps :)
Their gcd is one, which means that you can only make a single fruit basket without wasting fruit.
