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dybincka [34]
3 years ago
15

How do you write the expression multiply two and six then subtract 20

Mathematics
2 answers:
Anna007 [38]3 years ago
4 0

Answer:

(2 * 6) - 20

Step-by-step explanation:

<u>Step 1:  Convert words into an expression </u>

Multiply two and six then subtract 20

<em>(2 * 6) - 20 </em>

Answer:  (2 * 6) - 20

Oliga [24]3 years ago
3 0

Answer: 2(6) - 20

Step-by-step explanation:

Expression can be expressed as 2(6) - 20

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Complete the solution of the equation. Find the value of y when x equals -4. 5x + 2y = -20
guajiro [1.7K]
<span>5(-4) + 2y = -20
-20 + 2y = -20
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y = 0</span>
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What is 9 +10 equal to how much
AVprozaik [17]
Is equal to 19 u add the 9 plus the ten so u get 19
7 0
3 years ago
Read 2 more answers
when multiplie discount are used if an item is first discount by 40%,then again by 30%.then again by 10%,the final or cumulative
nadezda [96]
The answer is : 40+30=70
70+10=80 therfore the final or cumulative discount is 80%
4 0
3 years ago
A rectangle, a triangle, and two congruent semicircles were used to form the figure shown. Rectangle 5cm,20cmcircle : radius 5cm
Schach [20]

Answer:

The area of a shape is the amount of space it occupies

Step 1:

We start by calculating the area of the rectangle using:

\begin{gathered} A_{rectangle}=l\times b \\  \end{gathered}

By substituting the values, we will have

\begin{gathered} A_{rectangle}=l\times b \\ A_{rectangle}=20cm\times5cm \\ A_{rectangle}=100cm^2 \\ A_1=100cm^2 \end{gathered}

Step 2:

we calculate the area of the triangle using:

A_{triangle}=\frac{1}{2}\times base\times height

By substituting the values, we will have

\begin{gathered} A_{tr\imaginaryI angle}=\frac{1}{2}\times base\times he\imaginaryI ght \\ A_{tr\mathrm{i}angle}=\frac{1}{2}\times10cm\times8cm \\ A_{tr\mathrm{i}angle}=\frac{80cm^2}{2} \\ A_{tr\mathrm{i}angle}=40cm^2 \\ A_2=40cm^2 \end{gathered}

Step 3:

Calculate the area of the two semicircles

A_{semicircle}=\frac{\pi r^2}{2}

By substituting the values, we will have

\begin{gathered} A_{sem\imaginaryI c\imaginaryI rcle}=\frac{\pi r^{2}}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=3.14\times\frac{5^2}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=39.25cm^2 \\ Area\text{ of two semicircle will be} \\ A_3=39.25cm^2\times2 \\ A_3=78.5cm^2 \end{gathered}

Step 4:

Calculate the area of the shape

We will calculate the area of the shape by adding all the individual areas together

A_{shape}=A_1+A_2+A_3

By substituting the values, we will have

\begin{gathered} A_{shape}=A_{1}+A_{2}+A_{3} \\ A_{shape}=100cm^2+40cm^2+78.5cm^2 \\ A_{shape}=218.5cm^3 \end{gathered}

Hence,

The area of the shape will be

\Rightarrow218.5cm^2

4 0
1 year ago
Is (5,-4) a solution?<br><br> (I’ll mark you the brainliest!)
Airida [17]

Answer:oh it is - 5 I had this in my questions for homework

Step-by-step explanation:you have to multiply and subtract and do that many times

6 0
3 years ago
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